dcgirl16
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how do u find the height of an object thrown straight up if u are only given that it is thrown with a velocity of 30m/s
The discussion focuses on calculating the height of an object thrown straight up with an initial velocity of 30 m/s using energy conservation principles and equations of motion. The key equation derived is the kinetic energy (KE) equals potential energy (PE), expressed as 1/2 mv² = mgh. By simplifying, the height (h) can be calculated using the formula h = (1/2 v²) / g. Additionally, the equations of motion are introduced, specifically v² = u² + 2gs, where v is the final velocity, u is the initial velocity, g is the acceleration due to gravity, and s is the height reached.
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