How do we prove tangent lines to conics using homogeneous coordinates?

  • Context: Graduate 
  • Thread starter Thread starter erohanip
  • Start date Start date
  • Tags Tags
    Conics Lines Tangent
Click For Summary
SUMMARY

The discussion centers on proving the existence of tangent lines to conics using homogeneous coordinates, specifically referencing the proof from "Multiview Geometry" by Hartley and Zisserman. The proof involves the conic coefficient matrix C, defined as [ a, b/2, d/2 ; b/2, c, e/2 ; d/2, e/2, f ]. The key conclusion is that if a line l = Cx has one-point contact with the conic, it is a tangent; otherwise, if it intersects at another point y, the line must be degenerate, indicating it lies entirely on the conic. The confusion arises from the implications of the expression (x + αy)T C(x + αy) = 0, which needs further clarification.

PREREQUISITES
  • Understanding of homogeneous coordinates in projective geometry
  • Familiarity with conic sections and their properties
  • Knowledge of matrix operations, particularly with conic coefficient matrices
  • Basic grasp of the concept of tangents in geometry
NEXT STEPS
  • Study the properties of conic sections in detail, focusing on their geometric interpretations
  • Learn about homogeneous coordinates and their applications in projective geometry
  • Explore matrix algebra, particularly operations involving symmetric matrices
  • Investigate the derivation and implications of the expression (x + αy)T C(x + αy) = 0 in the context of conics
USEFUL FOR

Mathematicians, geometry enthusiasts, students studying projective geometry, and anyone interested in the properties of conics and their tangents.

erohanip
Messages
1
Reaction score
0
I am unable to comprehend the proof for tangent line to conics. Here is the proof as per the book (Multiview Geometry by Hartley and Zisserman). Everything is in homogeneous coordinates.


The line l = Cx passes through x, since lT x = xT Cx = 0. If l has one-point contact with the conic, then it is a tangent, and we are done. Otherwise suppose that l meets the conic in another point y. Then yT Cy = 0 and xT Cy = lTy = 0. From this it follows that (x + αy)T C(x + αy) = 0 for all α, which means that the whole line l = Cx joining x and y lies on the conic C, which is therefore degenerate.

where C is conic coefficient matrix = [ a, b/2, d/2 ; b/2, c, e/2 ; d/2, e/2, f ]

I don't see how the underlined portion follows from the above premise. And even if it does how is the line a tangent to the conic?
 
Physics news on Phys.org
Just multiply out the expression. The four terms xTCx, xTCy, yTCx, yTCy are all zero.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 21 ·
Replies
21
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 15 ·
Replies
15
Views
3K