How Do Wind and Plane Speeds Combine to Affect Ground Velocity?

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SUMMARY

The discussion focuses on calculating the ground velocity of a plane traveling at an airspeed of 285 km/h [E45ºS] with a northeast wind blowing at 75 km/h [N22ºE]. The preferred method for solving this problem is the resolution of vectors, which involves breaking down the vectors into their x and y components and applying the Pythagorean theorem. The initial calculations using the cosine law yielded a ground velocity of 265 km/h, but the resolution method led to confusion regarding the correct diagram and vector addition. The correct approach requires ensuring that the vectors are properly oriented and added according to vector addition rules.

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  • Understanding of vector resolution techniques
  • Familiarity with Pythagorean theorem applications
  • Knowledge of basic trigonometry, specifically sine and cosine functions
  • Ability to interpret vector diagrams accurately
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  • Study vector addition and resolution methods in physics
  • Practice problems involving airspeed and wind speed calculations
  • Learn how to accurately draw and interpret vector diagrams
  • Explore the effects of wind on aircraft navigation and performance
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Students studying physics, particularly those focusing on relative motion and vector analysis, as well as pilots and aviation enthusiasts interested in understanding the impact of wind on flight dynamics.

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Hi, I am having troubles with a question concerning relative motion. The problem goes:

A plane is traveling at an air speed of 285 km/h [E45ºS]. A wind is blowing to the northeast at 75 km/h [N22ºE] relative to the ground. Determine the velocity relative to the ground.

My teach prefers that we do not use the cosine law to determine the unknown vector, and instead requests that when we draw our diagram, we do something called the resolution of vectors. Which is separating the two vectors into x and y components, add the x's and y's together and use Pythagorean theorum to solve.

The cosine law provided me with the correct answer for this question, which was 265 km/h.

However, in using his method, my diagram (which was correct, and I have attached, to anyone who is confused), resembled a rectangle, and I came up with these calculations:

285/sin90 = x1/sin45
x1 = 202 km/h

x2/sin22 = 75/sin90
x2 = 28 km/h

Therefore, shouldn't x1 + x2 = 265 km/h ?
Please help me!
 

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Yeah, I'm confused by your diagram. Your directions don't look right (which way on the diagram is north?). Plus you haven't drawn the vectors as being added.

To add vectors... suppose your adding a vector B to vector A... The tail (part without the arrow) of B has to be placed at the head (part with the arrow) of A.

Draw the diagram again.
 

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