How Do You Apply Kirchhoff's Current Law to Find vx and ix in This Circuit?

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SUMMARY

The discussion focuses on applying Kirchhoff's Current Law (KCL) to determine the values of vx and ix in a specific circuit. The current source is given as is = 2 mA, leading to the conclusion that ix equals -2 mA. Subsequently, using the relationship vx = ixR, where R is 47 kΩ, the calculated voltage vx is -94V. The calculations are confirmed as correct based on the application of KCL.

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  • Basic circuit analysis techniques
  • Familiarity with Ohm's Law
  • Knowledge of electrical units (milliamps, volts, ohms)
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Homework Statement



[PLAIN]http://img24.imageshack.us/img24/4168/circuitv.png

Find vx and ix.


Homework Equations



Kirchhoff's Current Law: The algebraic sum of the currents entering a node is zero at any instant:

Σi = i1 + i2 +... iN = 0

The Attempt at a Solution


Since it's a current-driven circuit and ix points in the opposite direction of is,

ix = -is, where "is" is the current source.

We know that is = 2 mA, so... ix = -2 mA

... and vx = ixR
so vx = (-2 mA)(47 k ohms) = -94V

Is this right?
 
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