How Do You Balance Objects on a Uniform Board to Maintain Equilibrium?

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The discussion focuses on balancing a 15 kg uniform wooden board of length L at its center with a 6 kg object placed at one end. To maintain equilibrium, a 9 kg object must be positioned at a distance of L/3 from the balance point. The equation used to determine this is based on the principle of moments, specifically m1d1 = m2d2, where the mass of the board is uniformly distributed and does not influence the calculation.

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frfr1. Homework Statement
A 15 kg uniform wooden board of length L is balanced at its center. A 6 kg object is to be placed on the right end. How far from the balance point must a 9 kg object be placed to keep the board in equilibrium?

Homework Equations


##m_1d_1 = m_2d_2##

The Attempt at a Solution


Is it just ##6 \frac{L}{2} = 9 d_2##
##d_2 = \frac{L}{3}##? I guess I am not sure since they mention the weight of the wooden board, but since it is uniformly distributed, its weight shouldn't matter?
 
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srekai said:
frfr1. Homework Statement
A 15 kg uniform wooden board of length L is balanced at its center. A 6 kg object is to be placed on the right end. How far from the balance point must a 9 kg object be placed to keep the board in equilibrium?

Homework Equations


##m_1d_1 = m_2d_2##

The Attempt at a Solution


Is it just ##6 \frac{L}{2} = 9 d_2##
##d_2 = \frac{L}{3}##? I guess I am not sure since they mention the weight of the wooden board, but since it is uniformly distributed, its weight shouldn't matter?
You are right, and I like that you have recognized that the mass of the board does not affect the answer.
 
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