How Do You Calculate Acceleration and Initial Speed from Segment Times?

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SUMMARY

The discussion focuses on calculating acceleration and initial speed for an object moving with constant acceleration over two equal segments of 13 meters. The first segment is covered in 1.2 seconds, while the second takes 2.2 seconds. The calculated initial speed (V1) is 10.83 m/s, and the average speed (Vav) is determined to be 7.6 m/s. Consequently, the acceleration is computed as 2.24 m/s² using the formula acceleration = velocity/time.

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Homework Statement


An object moving along a straight line, at constant acceleration covers two equal, consecutive, 13 m long segments, the first one in t 1 = 1.2 s and the second one in t 2 = 2.2 s . What was the magnitude of acceleration? (in m/s2) ,
And what is the speed of the object (m/s) at the beginning of the first segment?



Homework Equations


V=(D/T)
if D/2 at V1, D/2 at V2, then
Vav = (2V1.V2)/V1+V2
acceleration = velocity/time


The Attempt at a Solution


V1 = 13/1.2 = 10.83 m/s
V2 = 13/2.2 = 5.91m/s
Vav = (2x10.83 x 5.91)/10.83 + 5.91 = 7.6
acceleration = 7.6 / 3.4
= 2.24 m/s2
 
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