How Do You Calculate Acceleration and Initial Speed from Segment Times?

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Homework Statement


An object moving along a straight line, at constant acceleration covers two equal, consecutive, 13 m long segments, the first one in t 1 = 1.2 s and the second one in t 2 = 2.2 s . What was the magnitude of acceleration? (in m/s2) ,
And what is the speed of the object (m/s) at the beginning of the first segment?



Homework Equations


V=(D/T)
if D/2 at V1, D/2 at V2, then
Vav = (2V1.V2)/V1+V2
acceleration = velocity/time


The Attempt at a Solution


V1 = 13/1.2 = 10.83 m/s
V2 = 13/2.2 = 5.91m/s
Vav = (2x10.83 x 5.91)/10.83 + 5.91 = 7.6
acceleration = 7.6 / 3.4
= 2.24 m/s2
 
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