How Do You Calculate Acceleration at t = 1/1.1 sec from the Given Equation R(t)?

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Homework Help Overview

The discussion revolves around calculating acceleration from a given position function R(t) at a specific time, t = 1/1.1 seconds. The context involves understanding the relationship between position and acceleration in the framework of physics, particularly in kinematics.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to clarify the problem statement and the specific time at which acceleration is to be calculated. There are questions regarding the transition from the position function to the acceleration and the interpretation of the time notation used.

Discussion Status

The discussion is ongoing, with participants seeking clearer explanations and attempting to understand the requirements of the problem. Some guidance has been offered regarding the need to clarify the problem statement and the time specification.

Contextual Notes

There is a noted confusion regarding the time expression used (1/1.1 seconds) and its implications for the calculation. Participants are also addressing the need for complete problem wording to facilitate better understanding.

mike32
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Homework Statement


All numerical constants are in the appropriate units, so that R (t) in units of meters, and a = 3.1 sec-1.

What is acceleration size (in meters per second ^ 2) t = 1 / 1.1 sec?

Note: When calculating sin (at), make sure the computer is in radian mode.

Homework Equations


R(t)= 8.4sin(at) +(3.1e^(-7t)) +6.9t^3

The Attempt at a Solution


Couldn't get to a solution
 
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Please try to explain this problem more clearly . Post the complete original wording of the problem as given to you if possible
 
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R (t) in meters and a= 3.1 sec^-1

What is its acceleration (m/s^2) in t = 1 / 1.1 seconds?
 
mike32 said:
What is its acceleration
How do you go from an expression for position to one for acceleration?
mike32 said:
t = 1 / 1.1 seconds?
Do you mean literally ##\frac {1}{1.1}## seconds? That is a very odd way to specify the time.
 
Last edited:
ok. but this is data in question.
 
mike32 said:
ok. but this is data in question.
Ok, so answer my first question.
 
Have to cut twice the equation and put t
 

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