How Do You Calculate and Graph the Derivatives of y = aK?

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SUMMARY

The discussion focuses on calculating and graphing the derivatives of the function y = aK, where a > 0. The first derivative, y', is determined to be a, indicating a constant slope, while the second derivative, y'', is 0, confirming that the graph is a horizontal line. Participants clarify that 'a' is a constant and not dependent on the variable K, which should ideally be represented as 'x' for clarity in standard mathematical notation.

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Homework Statement



y = aK, a >0... Find y' and y'' and graph.

Homework Equations



y = aK, a > 0

The Attempt at a Solution



Having a constant "a" there and then a > 0 confuses me for graphing.
y' = a
y" = 0

As for graphing, y' = a, a > 0... Perhaps just a straight horizontal line after a = 0?
 
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is y= y(k)?
 
939 said:

Homework Statement



y = aK, a >0... Find y' and y'' and graph.

Homework Equations



y = aK, a > 0

The Attempt at a Solution



Having a constant "a" there and then a > 0 confuses me for graphing.
y' = a
y" = 0
Assuming you mean K to be the independent variable, yes, these are correct.

As for graphing, y' = a, a > 0... Perhaps just a straight horizontal line after a = 0?
I don't know what you mean by "after a= 0". a is a constant and you are told that it is positive. It is never 0. You may be confusing "a" with the independent variable, K.

(I suspect this problem would have been must easier if they had just named the independent variable "x" and said "y= ax, a> 0", as is usual.)
 
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