How Do You Calculate and Graph the Derivatives of y = aK?

[939]

Homework Statement

y = aK, a >0... Find y' and y'' and graph.

Homework Equations

y = aK, a > 0

The Attempt at a Solution

Having a constant "a" there and then a > 0 confuses me for graphing.
y' = a
y" = 0

As for graphing, y' = a, a > 0... Perhaps just a straight horizontal line after a = 0?

 

[dirk_mec1]

is y= y(k)?

 

[HallsofIvy]

Homework Statement

y = aK, a >0... Find y' and y'' and graph.

Homework Equations

y = aK, a > 0

The Attempt at a Solution

Having a constant "a" there and then a > 0 confuses me for graphing.
y' = a
y" = 0

Assuming you mean K to be the independent variable, yes, these are correct.

As for graphing, y' = a, a > 0... Perhaps just a straight horizontal line after a = 0?

I don't know what you mean by "after a= 0". a is a constant and you are told that it is positive. It is never 0. You may be confusing "a" with the independent variable, K.

(I suspect this problem would have been must easier if they had just named the independent variable "x" and said "y= ax, a> 0", as is usual.)