How Do You Calculate Angular Acceleration and Displacement of a Rolling Ball?

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SUMMARY

The discussion focuses on calculating the angular acceleration and displacement of a solid ball with a diameter of 22 cm rolling without slipping. The initial angular velocity is 11 rad/s, and after 10 seconds, it decreases to 3 rad/s. The correct angular acceleration is determined to be -0.8 rad/s², with a linear displacement of 15.4 meters and a stopping time of 13.75 seconds. The confusion arose from incorrectly using the diameter instead of the radius in calculations.

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BlakeEdwards
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A solid ball with a diameter of 22 cm rolls along a horizontal surface as shown without slipping at a constant acceleration. It initially (t=0) has an angular velocity of 11 rad/s and 10 seconds later has an angular velocity of 3 rad/s.
(a)What is its angular acceleration? rad/s2
(b)What is the linear (translational) displacement of the ball? m
(c)How long (from t=0) will it take to stop? sec


I got -.8 rad/s^2
15.4 m
and 13.75 seconds

Im so confused, can someone help me please?
 
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Hi BlakeEdwards! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)

erm :redface: … you've used diameter instead of radius. :wink:
 

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