How Do You Calculate Bullet Speed in a Ballistic Spring System?

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SUMMARY

The discussion focuses on calculating the bullet speed (vB) in a ballistic spring system involving a spring with spring constant k, a block of mass M, and a bullet of mass m. The key equation derived is based on the conservation of energy principle, integrating kinetic energy (KE) and potential energy (Ug and Us). The initial attempt simplifies the equation to (1/2)mvi² = (1/2)kd², but acknowledges the need to incorporate gravitational effects and the mass of the block (M) for a complete solution.

PREREQUISITES
  • Understanding of conservation of energy principles in physics
  • Familiarity with kinetic energy (KE) and potential energy (Ug, Us) equations
  • Knowledge of spring mechanics and Hooke's Law
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the derivation of energy conservation equations in mechanical systems
  • Learn about the effects of gravitational potential energy in dynamic systems
  • Explore advanced spring dynamics and the implications of mass in energy equations
  • Investigate real-world applications of ballistic spring systems in engineering
USEFUL FOR

Students in physics, engineers designing ballistic measurement systems, and anyone interested in the dynamics of spring systems and energy conservation principles.

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Homework Statement


You have been asked to design a "ballistic spring system" to measure the speed of bullets. A spring whose spring constant is k is suspended from the ceiling. A block of mass M hangs from the spring. A bullet of mass m is fired vertically upward into the bottom of the block. The spring's maximum compression d is measured.

Find an expression for the bullet's speed vB.
Express your answer in terms of the variables m, M, k, d, and constant g.


Homework Equations


KE = (1/2)mv2
Ug = mgy
Us = (1/2)kx2

KEi + Ugi + Usi = KEf + Ugf + Usf

The Attempt at a Solution



This problem is going to end up getting really messy, but I am not sure how to incorporate the mass of the box (M) This is what I started with:

(1/2)mvi2 + mgyi + (1/2)kxi2 = (1/2)mvf2 + mgyf + (1/2)kxf2

now I'm assuming that mgy values are 0 because we are not given any value for the height the box is above the ground. so that would give:

(1/2)mvi2 + (1/2)kxi2 = (1/2)mvf2 + (1/2)kxf2

Incorporating the variables we are given:

(1/2)mvi2 = (1/2)kd2

however this does not include gravity (which I am sure needs to be included somewhere) or the mass of the box (M)
 
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i don't know if this help but maybe if you put the spring at rest at y=0 and then when it's compress the y=d you could incorporate then the mgy equitation therefore putting g and M in the equation
 

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