How Do You Calculate Capacitance and Inductance in a Transmission Line Model?

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To calculate the capacitance per unit length C and inductance per unit length L of a transmission line with a cylindrical conductor near a conducting plane, the approach involves superimposing electric and magnetic fields. The electric field is derived from the charges on the cylinder and plane, leading to the expression for capacitance as 1/C = (1/2πre0)ln[(d-r)/r] + (1/2e0)(d-r)/m. For inductance, the magnetic field is determined using Ampere's law, resulting in L = (v/2π)ln[(d-r)/r] + v(d-r)/m. The relationship 1/sqrt(LC) = c is confirmed through these calculations. The use of image theory is suggested to effectively model the charge distribution on the infinite plane.
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Homework Statement


A transmission line consists of a cylindrical conductor of radius r at a distance d in air from a conducting plane (r >>d).

Derive the capacitance per unit length C and the inductance per unit length L and
check that 1/sqrt(LC) = c.


Homework Equations





The Attempt at a Solution


I thought I could just give the cyclinder a charge -Q and the plane a charge +Q and superimpose the fields. So that along the line through the centre of the cylinder and normal to the plane, the field is:

E = -Q/(2.pi.r.l.e0) -Q/(2.l.m.e0)

Where l is the length of the cylinder and l, m are the dimensions of the plane.

Then integrating to find the potential difference and dividing by Q and multiplying by l gives:

1/C = (1/2.pi.r.e0)*ln[(d-r)/r] + (1/2e0)*(d-r)/m

Then the B due to the cylinder would be vI/2.pi.r where I am using v as permeability of free space. And on the normal through the centre line, it would be perpendicular to the line.

I think that on the line, the field from all the elements on the plane would superimpose to produce a field perpendicular to the line, which Ampere would then give as vI/m

So

B = vI/2.pi.r + vI/m

Then flux is the integral of that, and dividing by I and l gives L:

L = (v/2.pi)*ln[(d-r)/r] + v(d-r)/m

But this doesn't seem right.

Any help? Thanks.
 
Physics news on Phys.org
You can't assume that the charge on the plane would be uniformly distributed. However, since it is an infinite plane, you can use image theory to model the effective charge distribution.
 

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