How Do You Calculate Centripetal Force for Circular Motion?

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SUMMARY

The centripetal force required to rotate a 3 kg object in a circle with a radius of 3 m at one revolution per second is calculated to be 355.31 N. The calculation involves determining the tangential velocity using the formula v = 2πr, resulting in a velocity of approximately 18.85 m/s. The centripetal force is then derived using the formula F = mv²/r. An alternative method using angular velocity (ω) is also suggested, emphasizing the importance of understanding the relationship between linear and angular motion.

PREREQUISITES
  • Understanding of centripetal force and its formulas (F = mv²/r, F = mω²r)
  • Knowledge of circular motion concepts, including radius and period of rotation
  • Ability to convert between linear velocity and angular velocity
  • Familiarity with basic physics equations and units
NEXT STEPS
  • Learn about angular velocity and its application in circular motion
  • Study the relationship between linear and angular motion in physics
  • Explore additional resources on centripetal force, such as the MIT Open Courseware on Classical Mechanics
  • Review the Wikipedia page on centripetal force for alternative formulas and explanations
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of circular motion and centripetal force calculations.

joe465
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Homework Statement



Calculate the centrepetal force required to rotate a3kg object in a circle at a radius of 3m at one revolution per second.

Homework Equations



MV2/r
2*pie*r

The Attempt at a Solution



First i presume i must convert the revolution per second into metres per second.

Calculate the circumference.

2*pie*r
2*pie*3
18.84955592153876m

Since its one revolution per second then it would mean:

18.84955592153876ms-1

Now for centrepetal force:

mv2/r

3*18.84955592153876 squared/3

1065.9172753176507952118585470128 / 3

Centrepetal force = 355.31N (2dp)


I hope this is right, the circular motion stuff still has never sunk in

Thanks, Joe
 
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Your calculation of the tangential velocity v is incorrect, you should use v= rω and then put that into F=mv2/r or F=mω2r for a more direct approach.
 
Looks good to me. :smile:
 
rock.freak667 said:
Your calculation of the tangential velocity v is incorrect,
Why do you say that?
 
Doc Al said:
Why do you say that?

Nevermind, my bad, I used rpm instead of what it was rps.
 
That's quite right. I would have written 355.3 N, but that's just my "three significant figures" training.

MIT Open Courseware has an excellent lecture series on Classical Mechanics, with a great video on circular motion.
 
joe465 said:

Homework Statement



Calculate the centrepetal force required to rotate a3kg object in a circle at a radius of 3m at one revolution per second.

Homework Equations



MV2/r
2*pie*r

The Attempt at a Solution



First i presume i must convert the revolution per second into metres per second.

Calculate the circumference.

2*pie*r
2*pie*3
18.84955592153876m

Since its one revolution per second then it would mean:

18.84955592153876ms-1

Now for centrepetal force:

mv2/r

3*18.84955592153876 squared/3

1065.9172753176507952118585470128 / 3

Centrepetal force = 355.31N (2dp)


I hope this is right, the circular motion stuff still has never sunk in

Thanks, Joe

There are many texts and references that show it, but if you look at the following wiki reference - the formulas right at the start - you will see that there is another formula for centripetal force that can be used in exactly this situation - when you know the Period of rotation rather than how fast it is travelling. That means you can't make a mistake calculating v, because you never calculate it!

http://en.wikipedia.org/wiki/Centripetal_force
 

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