How Do You Calculate Centripetal Force for Circular Motion?

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Homework Help Overview

The discussion revolves around calculating the centripetal force required for a 3 kg object rotating in a circle with a radius of 3 m at a rate of one revolution per second. Participants are exploring the relevant equations and the conversion of rotational speed into linear velocity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • One participant attempts to calculate the centripetal force using the formula mv²/r after determining the linear velocity from the circumference. Others question the accuracy of the velocity calculation and suggest alternative approaches using angular velocity.

Discussion Status

There are differing opinions on the correctness of the initial calculations, with some participants providing guidance on alternative methods. The conversation includes acknowledgment of potential misunderstandings regarding the conversion of rotational speed.

Contextual Notes

Participants are discussing the implications of using revolutions per second versus revolutions per minute and the significance of significant figures in reporting the final answer. There is a reference to external resources that may aid in understanding the concepts involved.

joe465
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Homework Statement



Calculate the centrepetal force required to rotate a3kg object in a circle at a radius of 3m at one revolution per second.

Homework Equations



MV2/r
2*pie*r

The Attempt at a Solution



First i presume i must convert the revolution per second into metres per second.

Calculate the circumference.

2*pie*r
2*pie*3
18.84955592153876m

Since its one revolution per second then it would mean:

18.84955592153876ms-1

Now for centrepetal force:

mv2/r

3*18.84955592153876 squared/3

1065.9172753176507952118585470128 / 3

Centrepetal force = 355.31N (2dp)


I hope this is right, the circular motion stuff still has never sunk in

Thanks, Joe
 
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Your calculation of the tangential velocity v is incorrect, you should use v= rω and then put that into F=mv2/r or F=mω2r for a more direct approach.
 
Looks good to me. :smile:
 
rock.freak667 said:
Your calculation of the tangential velocity v is incorrect,
Why do you say that?
 
Doc Al said:
Why do you say that?

Nevermind, my bad, I used rpm instead of what it was rps.
 
That's quite right. I would have written 355.3 N, but that's just my "three significant figures" training.

MIT Open Courseware has an excellent lecture series on Classical Mechanics, with a great video on circular motion.
 
joe465 said:

Homework Statement



Calculate the centrepetal force required to rotate a3kg object in a circle at a radius of 3m at one revolution per second.

Homework Equations



MV2/r
2*pie*r

The Attempt at a Solution



First i presume i must convert the revolution per second into metres per second.

Calculate the circumference.

2*pie*r
2*pie*3
18.84955592153876m

Since its one revolution per second then it would mean:

18.84955592153876ms-1

Now for centrepetal force:

mv2/r

3*18.84955592153876 squared/3

1065.9172753176507952118585470128 / 3

Centrepetal force = 355.31N (2dp)


I hope this is right, the circular motion stuff still has never sunk in

Thanks, Joe

There are many texts and references that show it, but if you look at the following wiki reference - the formulas right at the start - you will see that there is another formula for centripetal force that can be used in exactly this situation - when you know the Period of rotation rather than how fast it is travelling. That means you can't make a mistake calculating v, because you never calculate it!

http://en.wikipedia.org/wiki/Centripetal_force
 

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