How Do You Calculate Charge Using Coulomb's Law?

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SUMMARY

This discussion focuses on calculating charge using Coulomb's Law, specifically addressing the manipulation of the equation by dividing both sides by a common factor, q4. The participants confirm that this approach simplifies the equation to isolate the charges involved. The final calculated charge is noted to be slightly more than -4*10^-5 C, indicating a potential calculation error by one participant. The discussion emphasizes the importance of precise calculations in applying Coulomb's Law.

PREREQUISITES
  • Understanding of Coulomb's Law and its mathematical formulation
  • Familiarity with basic algebraic manipulation of equations
  • Knowledge of electric charge units, specifically coulombs (C)
  • Ability to interpret and manipulate scientific notation
NEXT STEPS
  • Study the derivation and applications of Coulomb's Law in electrostatics
  • Learn about the significance of constants like k (Coulomb's constant) in calculations
  • Explore common errors in charge calculations and how to avoid them
  • Investigate the implications of charge interactions in real-world scenarios
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Students in physics, educators teaching electrostatics, and anyone involved in calculations related to electric charges and forces.

th77
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I attached my message and the problem in a Word document because I don't know how to enter equations in this text box.

Thanks for your help
 

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Yeah your working is generally fine.

You can assign q4 a value, but it doesn't matter since it is a common factor throughout the whole equation. So what you do is you divide the LHS and RHS of your equation by q4. This leaves:

\frac {kq_4q_1} {q_4 (r_1_4)^2} - \frac {kq_4q_2} {q_4 (r_2_4)^2} + \frac {kq_4q_3} {q_4(r_3_4)^2} = 0/q4

ie \frac {kq_1} {(r_1_4)^2} - \frac {kq_2} {(r_2_4)^2} + \frac {kq_3} {(r_3_4)^2} = 0

Anyway even doing it your way you should have got the same value as me, but you didn't. I got something closer to -4*10^-5 C (this isn't the answer). The actual answer is slighty more than -4*10^-5 C. So you must have made a simple calculating error.
 

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