How Do You Calculate cos(a-b) from Given Sine and Cosine Values?

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To calculate cos(a-b) from the given sine and cosine values, the Pythagorean identity cos²b + sin²b = 1 can be utilized to express sin(a) in terms of sin(b). The initial equations provided are sin(a) + cos(b) = 31/2/2 and sin(a) + sin(b) = 3/2. After applying the identity, two solutions were found: approximately 0.2599 and 0.7858, while the expected answer was 0.5. There is speculation about a possible typo in the original problem or the provided answer, as multiple users arrived at the same decimal approximation. The discussion highlights the complexity of deriving cos(a-b) from the given values.
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Homework Statement



Given that
sin(a) + cos(b) = 31/2/2 and
sin(a) + sin(b) = 3/2

Find cos(a-b)

Homework Equations





The Attempt at a Solution



Can anyone give me some hints?
 
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See: http://file.glpacademy.co.kr/eTAP/mathfiles/english/trigo/lesson2/instructiontutor_last.html

ehild
 
Last edited by a moderator:
Try taking the Pythagorean identity
cos2 b + sin2 b = 1

and rewriting it in terms of sin a. I found an answer by starting this way, but it is a decimal approximation.
 
The answer i get is 0.7858... but the answer given is 0.5. What answer do you guys get?
 
Last edited:
0.7858... is what I got, too. Maybe there is a typo in the original problem or in the answer?
 
I get a total of 2 solutions: 0.2599 and 0.7858
 

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