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[SOLVED] Stuck on damped pendulum question...
A pendulum of length 1.00m is released at an angle of 15.0 degrees. After 1000 seconds, it's amplitude is decreased to 5.50 degrees due to friction. What is the value of [tex]b/2m[/tex]?
w = [tex]\sqrt{w_{0}^{2} - (b/2m)^{2}}[/tex]
x(t) = Asin(wt)
[tex]w_{0} = \sqrt{g/L}[/tex]
I have attempted this problem from a few angles, but I don't think I'm on the right track. I am assuming that I must treat the pendulum as a simple harmonic oscillator, making the original amplitude [tex]\Pi[/tex]
/12, and the amplitude after 1000s [tex]\Pi[/tex]/32.2. I am just not sure what to do next.
Any help is appreciated, I have a feeling I might be making this a little harder than it has to be, the answer is 1.00 * 10^-3 s^-1
EDIT
I am starting to think I can just get away with using the equation x = Ae[tex]^-(b/2m)t[/tex], but it still seems like I do not have enough information to answer this problem yet...
Thanks
Homework Statement
A pendulum of length 1.00m is released at an angle of 15.0 degrees. After 1000 seconds, it's amplitude is decreased to 5.50 degrees due to friction. What is the value of [tex]b/2m[/tex]?
Homework Equations
w = [tex]\sqrt{w_{0}^{2} - (b/2m)^{2}}[/tex]
x(t) = Asin(wt)
[tex]w_{0} = \sqrt{g/L}[/tex]
The Attempt at a Solution
I have attempted this problem from a few angles, but I don't think I'm on the right track. I am assuming that I must treat the pendulum as a simple harmonic oscillator, making the original amplitude [tex]\Pi[/tex]
/12, and the amplitude after 1000s [tex]\Pi[/tex]/32.2. I am just not sure what to do next.
Any help is appreciated, I have a feeling I might be making this a little harder than it has to be, the answer is 1.00 * 10^-3 s^-1
EDIT
I am starting to think I can just get away with using the equation x = Ae[tex]^-(b/2m)t[/tex], but it still seems like I do not have enough information to answer this problem yet...
Thanks
Last edited: