How Do You Calculate Energy and Speed of a Roller Coaster at Different Points?

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SUMMARY

The discussion focuses on calculating the energy and speed of a roller coaster at various points, specifically points B, C, and D, using gravitational potential energy and kinetic energy formulas. The roller coaster has a mass of 40,000 kg and starts from rest at a height of 54 m. The calculations yield the following results: at point B, kinetic energy (Ek) is 1.5x107 J, gravitational potential energy (Eg) is 5.9x106 J, and speed (V) is 28 m/s; at point C, Eg is 1.8x107 J, but the calculated Ek of 2.7x106 J is incorrect compared to the expected 2.4x106 J; at point D, Ek is 7.2x106 J, Eg is 1.4x107 J, and V is 19 m/s.

PREREQUISITES
  • Understanding of gravitational potential energy (Eg = M x g x h)
  • Knowledge of kinetic energy formula (Ek = 0.5 x M x V2)
  • Familiarity with total energy calculations (ET = Eg + Ek)
  • Basic physics concepts related to motion and energy conservation
NEXT STEPS
  • Review the principles of energy conservation in mechanical systems
  • Practice calculations involving gravitational potential energy and kinetic energy
  • Explore the effects of friction on energy calculations in roller coasters
  • Investigate real-world applications of energy calculations in amusement park rides
USEFUL FOR

Students studying physics, educators teaching energy concepts, and anyone interested in the mechanics of roller coasters and energy transformations.

Amjad1112
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Homework Statement


A 4.0X104 (or 40,000) Kg roller coaster starts from rest at point A. Neglecting friction, calculate its potential energy relative to the ground, its kinetic energy and speed at points B, C, and D.

http://img189.imageshack.us/img189/6162/1234q.png
(scanned Image, if you can't see the first number its 54 m)
The answers are given =
Point B:
Ek = 1.5x107 J
Eg = 5.9x106 J
V = 28 m/s
Point C:
Ek = 2.4x106 J
Eg = 1.8x107 J
V = 11 m/s
Point D:
Ek = 7.2x106 J
Eg = 1.4x107 J
V = 19 m/s

Homework Equations


Gravitational Potential Energy = Mass X Gravity X height or Eg= M X g X h
Kinetic Energy = 1/2 MV2 or Ek= 0.5 X M X V2
Total Energy = Gravitational Potential Energy + Kinetic Energy Or ET= Eg + Ek



The Attempt at a Solution


OK so i got Point B right
But the problem is point C

Point A: is the Total energy so to get it
Eg= 40,000 X 9.81 X 54
Ek = 0 Because its at rest
Et= Eg + Ek
Et = 21189600

Point B:
Eg= 40,000 X 9.81 X 15
Eg= 5886000 Or 5.9x106 Which is the answer they gave us
Ek= 21189600 - 5886000
Ek= 15303600 or 1.5x107 Which is also the right answer
Ek= 1/2 MV2
15303600=(0.50)(40,000) V2
765.18 = V2
27.6 = V or 28 Which is the right answer

Point C:
Eg= 40,000 X 9.81 X 47
Eg= 18442800 or 1.8x106 Which is the right answer
Ek= ET - Eg
Ek= 21189600 - 18442800
Ek= 2746800 or 2.7x106 Which is WRONG because the answer is 2.4x106

What do you think?
 
Last edited by a moderator:
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Amjad1112 said:
Point C:
Eg= 40,000 X 9.81 X 47
Eg= 18442800 or 1.8x106 Which is the right answer
Ek= ET - Eg
Ek= 21189600 - 18442800
Ek= 2746800 or 2.7x106 Which is WRONG because the answer is 2.4x106

What do you think?
Your answer looks correct to me.
 

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