How Do You Calculate Fluid Velocities in Diverging Pipes?

In summary, the problem involves flow in three pipes with the same length, friction factor, and on the same horizontal level. The pipes have different diameters, with the two parallel pipes having a diameter that is half the first pipe. The pressure at the outlet of the parallel pipes is equal to atmospheric pressure and minor losses can be neglected. Using the given information, including the density of the fluid, we can use the continuity and Bernoulli equations to find the velocities in all three pipes. To solve the problem, we can rewrite the equations to eliminate one of the unknown velocities and express it in terms of the other two.
  • #1
andz
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Homework Statement


Flow in a pipe splits into two parallel pipes. All three pipes have same length L, and same friction factor f. Diameter of first pipe is D. The two parallel pipes have diameter D and D/2. All three pipes are on same horizontal level. At the outlet of the two parallel pipes, the pressure is equal to atmospheric pressure. Minor losses can be neglected. The density of the fluid is constant. In this situation we can use this information: D = 0.03 meters, f = 0.02, L = 8 meters, pressure head at inlet of first pipe = 2 meters, g = 9.8 m/s^2.

I need to find the velocities in all three pipes.

Homework Equations


Continuity equation.
Bernoulli equation.
Darcy-Weisbach equation

The Attempt at a Solution


Due to conservation of mass, the continuity equation gives: Q1 = Q2 + Q3. This gives 1) A1V1 = A2V2 + A3V3.
Then I tried to apply bernoulli equation from inlet of the first pipe to outlet of both parallel pipes.
2) H1 - hf = H2 (H1 = total head at inlet of first pipe, hf = friction loss in pipe).
3) H1 - hf = H3

2) 2 + (V1^2)/2g - (fLV1^2)/2gD - (fLV2^2)/2gD) = (V2^2)/2g
3) 2 + (V1^2)/2g - (fLV1^2)/2gD - (fLV3^2)/2gD) = (V3^2)/2g
Is this correct so far and how do i solve this?
 
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  • #2
Hello Andz, :welcome:

Looks good to me so far. You have 3 equations with three unknowns. Be careful not to use D for two different diameters.
I would rewrite 2) - 3) to eliminate v32 and express it in v22.
 

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