How Do You Determine Forces in a Truss Structure?

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SUMMARY

The discussion focuses on determining the forces in a truss structure, specifically using the equilibrium equations Fx = 0 and Fy = 0. The user calculates angles θ and Φ using trigonometric functions, resulting in θ = 36.87° and Φ = 53.13°. However, the user struggles with diagramming the forces and requests assistance in visualizing the truss to sum the x and y forces effectively. The discussion emphasizes the importance of resolving forces into their horizontal and vertical components using F_x = Fcos(θ) and F_y = Fsin(θ).

PREREQUISITES
  • Understanding of truss structures and their components
  • Knowledge of static equilibrium principles in physics
  • Proficiency in trigonometry, specifically tangent functions
  • Familiarity with force resolution techniques in mechanics
NEXT STEPS
  • Study the method of joints in truss analysis
  • Learn to create free body diagrams for truss members
  • Explore the use of software tools like AutoCAD for structural analysis
  • Investigate the principles of vector resolution in physics
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Engineering students, structural analysts, and anyone involved in mechanical design or civil engineering who needs to understand truss force determination.

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Homework Statement


Determine the forces in each member of the truss shown. Also find the values for any reactant forces

http://img201.imageshack.us/img201/6853/trussnu9.jpg

Homework Equations



Fx= 0
Fy= 0

The Attempt at a Solution



I set θ in the corner of J1
tan θ=12/16
θ = tan-1 12/16
θ = 36.87

I set Φ in the corner of J3
tan Φ = 12/9
Φ = tan-1 12/9
Φ = 53.13

This is where I began to falter. I could not figure out how to diagram everything out. If someone could just at least give me a diagram of where things are supposed to go, I can sum up the x and y forces by myself. This is pretty urgent, and I was absent for this class so my only help is messy notes from another student. This isn't in my textbook. Any help will be appreciated.
 
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You want to resolve the forces. If a force F makes an angle \theta with the horizontal, the horizontal force is F_x=Fcos\theta and the vertical force is F_y=Fsin\theta.

Give us something to work on and we'll lead you on.
 

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