How Do You Calculate Moment of Inertia for Different Axes?

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Homework Help Overview

The discussion revolves around calculating the moment of inertia for different axes related to a system of masses. The original poster presents two specific scenarios involving the calculation of moment of inertia for axes passing through different masses.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the moment of inertia formula, I=mr^2, and question the distances used in calculations. There is an exploration of whether the center of mass is relevant to the problem.

Discussion Status

Some participants have provided guidance on calculating the moment of inertia for each mass and summing them. Questions have been raised regarding the correct application of the formula, particularly about squaring the distances and the relevance of dividing by total mass.

Contextual Notes

Participants are navigating through the specifics of the problem setup, including the axis of rotation and the distances involved. There is an indication of confusion regarding the center of mass and its relation to the calculations being performed.

mcnealymt
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Homework Statement



a)Find the moment of inertia about an axis that passes through mass A and is perpendicular to the page. In kg m^2

b)Find the moment of inertia about an axis that passes through masses B and C.In kg m^2

http://session.masteringphysics.com/problemAsset/1070524/4/12.EX16.jpg

Homework Equations



I=mr^2

The Attempt at a Solution



a) (Mass of a * r + Mass of b * r)/ (Total Mass)

.005 They wanted the answer in two sigfigs so I put .05*10^-1 and it was wrong.

b) Used Pythagorean Theorem

sqrt(.10^2- .062)= .08
 
Last edited:
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mcnealymt said:
I=mr^2
Good. Just find I for each mass (around the given axis) and add them up to get the total I.

a) (Mass of a * r + Mass of b * r)/ (Total Mass)
You forgot to square the distances. What distance did you use? And why did you divide by the total mass?
 
Doc Al said:
Good. Just find I for each mass (around the given axis) and add them up to get the total I.


You forgot to square the distances. What distance did you use? And why did you divide by the total mass?
That makes sense, for some reason I was trying to find the center of mass which is completely irrelevant.

The distances I used were for a were: (.1kg)(.1m)^2+ (.1kg)(.1m)^2


The distance used for b was .08m (found using Pythagorean)
(.08m)^2(.2kg)
 
Thank you Doc Al, I appreciate it. Have a nice day.
 

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