How Do You Calculate Orbital Dynamics for a Satellite Around Planet X?

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Homework Help Overview

The discussion revolves around calculating various aspects of orbital dynamics for a satellite orbiting Planet X, which has specific mass and radius values. The original poster presents a set of questions related to gravitational force, acceleration, orbital speed, and period of the satellite.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply gravitational formulas and kinematic equations to find the required values but expresses uncertainty about the correct data to use. Some participants question the accuracy of the values substituted in the calculations and suggest a careful review of the problem statement.

Discussion Status

Participants are actively engaging with the problem, with some providing hints and guidance on checking the values used in calculations. There is an ongoing exploration of the correct interpretation of the variables involved, particularly regarding the mass of the planet and the radius used in the equations.

Contextual Notes

There are indications of confusion regarding the appropriate values to use for mass and radius, as well as the interpretation of the radius in the context of the problem. The original poster seeks clarification on these points, highlighting a need for careful reading of the problem statement.

thelightsare
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Homework Statement



Planet X has a mass of 6.42x10^20 kg and a radius of 2400km. A satellite with a mass of 1500kg is in orbit around Planet X at an altitude of 300km.
a) what is the Force of Gravity?
b) What is the acceleration of the satellite while in orbit?
c) Find the speed of the satellite in orbit.
d) Find the period of the satellite.


Homework Equations



F = GMm/r^2, maybe f=ma , a = v^2/r?, T= 2 pi r/v

The Attempt at a Solution



a)
F=GMm/r^2
F=6.67e-11*6.42e23*2000/(3400+300)^2
F[tex]\approx[/tex]6.26e9 N ?

b) very unsure but can you use
f=ma
6.26e9 N=2000a
and solve for a or is tht wrong? I was also maybe thingking of using

c) v = ?
could you use a = v^2/r
a(take answer from b) = v^2/(3400+300) and solve for v
or is this the wrong equation or wrong values?

d)T= 2 pi r/v
T = 2 pi (3400+300)/v(answer from c) ?

Thanks!
 
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Your method is correct, but the numbers you plugged in for the masses and radius of the planet do not much with the data given.

ehild
 
ehild said:
Your method is correct, but the numbers you plugged in for the masses and radius of the planet do not much with the data given.

ehild
I always have a problem telling which data to use. Any hints or suggestions?
 
thelightsare said:
I always have a problem telling which data to use. Any hints or suggestions?

Seriously? How about reading the question carefully, using the data that's provided, and checking your figures?

There is no magic formula to help with that!
 
gneill said:
Seriously? How about reading the question carefully, using the data that's provided, and checking your figures?

There is no magic formula to help with that!

I just really have trouble deciding which mass to use and wether "r" would mean to use the dist. between objects or the radius. I really really really want to understand and would love any help! Also, how do u check ur answers? It seems like valuable information to know.
 
Read the text of the problem and compare with the data you used when calculating the force: the mass of the planet is 6.42x10^20 kg. It is M. You substituted 6.42x10^23 kg for M. The mass of the satellite is 1500 kg. You substituted 2000 kg for m. The radius of the planet is 2400 m. You plug in 3400 m. ehild
 
ehild said:
Read the text of the problem and compare with the data you used when calculating the force: the mass of the planet is 6.42x10^20 kg. It is M. You substituted 6.42x10^23 kg for M. The mass of the satellite is 1500 kg. You substituted 2000 kg for m. The radius of the planet is 2400 m. You plug in 3400 m.


ehild

Oh! THank you so much!
 
One quick last question. For a = v^2/r and T= 2 pi r/v would r =2400+300 or just 2400?
 
r=2700 km

ehild
 
  • #10
ehild said:
r=2700 km

ehild

Great! Thanks so much
 

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