How Do You Calculate Retarded Vector Potential for a Current-Carrying Loop?

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Homework Statement


a wire bent into a loop it looks like [URL]http://www.pitt.edu/~medart/menuglossary/arch.htm[/URL] it carries a current increases linearly with time I=kt calc retarded vector potentaik

Homework Equations


A=[tex]\mu[/tex]o/4[tex]\pi[/tex] [tex]\int[/tex](k(T-r/c))/r) dl

The Attempt at a Solution


I just don't understand one part.
so i have 4 integrals first one is for the small arch second one is the length third bigger arch and last the other length on the other side.
so i have [tex]\int[/tex]dl/r r is radius and so the smaller radius is a and i just have
1/a [tex]\int[/tex]dl I am not sure what the integration is to in the book, they have dl=2a x^ i am not seeing how they got 2a then the straight line dx/x same for here not sure why they integrate it from a to b they got ln b/a

Also for a similar problem but with straight line why did they add a factor of 2?
A=[tex]\mu[/tex]o/4[tex]\pi[/tex] 2z^ [tex]\int[/tex](k(T-r/c))/r) dz
 
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they get ln|b/a| because they are integrating over that straight line segment at distance x away, and the radius changes from a to b . But they did it in Cartesian so they go from -b to -a but the negatives cancel once inside the log. As for the factor of 2 in the other parts i will have to think about it . But on those 2 arcs you would be integrating over the angle correct.
 
to late already had my final lol thanks anyways
 
Ya this was a problem out of Griffiths , I had to do this problem like a month ago.
 
yeah it is was just reviewing for finals
 
I was just working on this two weeks ago in Griffiths. I was going to post but I saw your response. Even after the finals, you should still try to learn it.
 
lol ok so how do u find the integrations?