How Do You Calculate Temperature Difference Using a Thermocouple?

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SUMMARY

The temperature difference between the two liquids can be calculated using the thermocouple's sensitivity. Given a voltage reading of 1.35mV and a sensitivity of 0.05mV/C, the temperature difference is determined by dividing the voltage by the sensitivity. This results in a temperature difference of 27°C, confirming that the calculation method is accurate and straightforward.

PREREQUISITES
  • Understanding of thermocouples and their operation
  • Knowledge of voltage measurement techniques
  • Familiarity with temperature conversion principles
  • Basic algebra for solving equations
NEXT STEPS
  • Research the principles of thermoelectric effects in thermocouples
  • Learn about different types of thermocouples and their sensitivities
  • Explore voltage-to-temperature conversion equations in thermocouple applications
  • Investigate the calibration methods for thermocouples
USEFUL FOR

Students in physics or engineering, technicians working with temperature measurement devices, and anyone involved in thermocouple applications or temperature monitoring systems.

Puny
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Homework Statement



The one end of the thermocouple is placed in 45C water, the other end in oil of unknown temperature. Of the voltmeter connected to it's end I got 1.35mV. If the sensitivity of the thermocouple is 0.05mV/C, what will the difference of temperature of the liquids be?


Homework Equations



This is really what I'm looking for. Not sure at all what equation I would use.


The Attempt at a Solution



Would doing something like:
1.35mV / 0.05mV/C = 27C
Would 27C be the difference

Thanks for any input
 
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I don't see what else could it be. What does your textbook say?
 

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