How Do You Calculate Temperature Difference Using a Thermocouple?

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Puny
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Homework Statement



The one end of the thermocouple is placed in 45C water, the other end in oil of unknown temperature. Of the voltmeter connected to it's end I got 1.35mV. If the sensitivity of the thermocouple is 0.05mV/C, what will the difference of temperature of the liquids be?


Homework Equations



This is really what I'm looking for. Not sure at all what equation I would use.


The Attempt at a Solution



Would doing something like:
1.35mV / 0.05mV/C = 27C
Would 27C be the difference

Thanks for any input
 
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