How Do You Calculate Tension in a Descending Elevator?

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    Elevator Tension
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SUMMARY

The discussion focuses on calculating the tension in a rope of an elevator that is accelerating downward at a constant acceleration of 1.4 m/s². The mass of the elevator is 2003 kg, and the gravitational acceleration is -9.8 m/s². The correct formula for tension (T) is derived from the equation T + 2003(-9.8) = 2003(1.4), leading to a calculated tension of 22433.6 N. The tension in the rope decreases as the elevator accelerates downward, approaching zero during free fall.

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yosette_ledezma
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So I am really stuck on this physics problem, its an elevator that is accelerating downward at a constant acceleration and I need to find the Tension on the rope

T=?
m=2003kg
a=1.4m/s^2
g=-9.8

T+2003(-9.8)=2003(1.4)
T=22433.6
What am i doing wrong?
 
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If it is accelerating downwards, should the tension in the rope get more or less?
Hint - what would be the tension in the rope be if the elevator was free falling?
 

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