How Do You Calculate Tension in Strings Supporting a Meter Stick in Equilibrium?

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SUMMARY

The discussion focuses on calculating the tension in two strings supporting a uniform meter stick in equilibrium. The meter stick has a mass of 180 g, which converts to 0.18 kg, resulting in a gravitational force of 1.764 N using the formula F=mg. The key principle highlighted is that the sum of the vertical forces must equal zero, which is essential for solving the tension in both strings at the 0 cm and 90 cm marks.

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  • Understanding of Newton's laws of motion
  • Familiarity with the concept of equilibrium in physics
  • Basic knowledge of force calculations using F=mg
  • Ability to analyze free body diagrams
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  • Explore tension calculations in various support scenarios
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the mechanics of tension in strings and equilibrium scenarios.

dance0486
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Homework Statement


A uniform meter stick with a mass of 180 g is supported horizontally by two vertical strings, one at the 0 cm mark and the other at the 90 cm mark. What is the tension in the string at 0 cm and at 90 cm?



2. The attempt at a solution I changed 180 g to .18 kg. Using F=mg, I found mg=1.764 N. From there, I have made numerous attempts, but none make sense! I am making this problem way harder than it should be. Please help!
 
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Sorry, I also know that the sum of the forces needs to be 0; and there is only forces in the y direction.
 

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