How Do You Calculate the EMF of a Cell in a Circuit?

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Homework Help Overview

The discussion revolves around calculating the electromotive force (EMF) of a cell within a circuit, specifically focusing on a circuit diagram that includes resistors and internal resistance. Participants are exploring the application of Kirchhoff's laws in this context.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to apply the equation EMF = I(R + r) but express uncertainty about its validity. There are questions regarding the application of Kirchhoff's laws and the interpretation of voltage readings across resistors. Some participants are confused about the signs of voltage readings and the implications of internal resistance.

Discussion Status

The discussion is active, with participants sharing their interpretations and questioning the assumptions behind their calculations. Some guidance has been offered regarding the need to apply Kirchhoff's laws, but there is no clear consensus on the correct approach or understanding of the concepts involved.

Contextual Notes

Participants mention specific voltage readings and resistances but express confusion about how these relate to the overall EMF calculation. There is a lack of clarity regarding the definitions and applications of Kirchhoff's voltage law, which is central to the problem at hand.

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I know I need to find the difference of of the volts about the 2 resistors.

it ends up being 1 volt, but how the hell does i(R+r)=emf come into that
 
DeanBH said:
I know I need to find the difference of of the volts about the 2 resistors.

it ends up being 1 volt, but how the hell does i(R+r)=emf come into that
That equation is valid only for two resistors in series, i.e. where a cell has an internal resistance r and is connected to a load resistance R.

As I said previously, you need to apply Kirchoff's laws here.
 
I did, the answer is 1

just doesn't make sense.
 
DeanBH said:
I did, the answer is 1

just doesn't make sense.
I also have emf = 1V. So what doesn't make sense?
 
Why do i have to count one of those volt readings as negative, and why inst it 1/r it looks like a a parallel
 
DeanBH said:
Why do i have to count one of those volt readings as negative, and why inst it 1/r it looks like a a parallel
What is Kirchoff's voltage/loop law?
 
Hootenanny said:
What is Kirchoff's voltage/loop law?

no idea
 
  • #10
Hootenanny said:
As I said previously, you need to apply Kirchoff's laws here.
DeanBH said:
I did, the answer is 1
Hootenanny said:
What is Kirchoff's voltage/loop law?
DeanBH said:
no idea
How can you apply Kirchoff's voltage law if you don't know what it is?
 
  • #11
guessed, that the volts in the battery would have to make up for the difference. but why is the amps 0.06 out of 0.032, if the volts were 5.2 instead of 4.2 in the right part of the circuit it wouldn't fit the rule RI=v
 
Last edited:

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