How Do You Calculate the Equivalent Capacitance in Mixed Capacitor Circuits?

[CR9]

Please help :( -Capacitors in series and parallel

Homework Statement

Find the relationship between C and C1 to make C equivalent= C

The diagram is as shown below:-

                                           C1 
               A---------------------------||----
                                        |                |
                                         =C1            = C
                                        |                |
                B---------------------------------

Homework Equations

C parallel= C1 + C2 + C3...
1/C series= 1/C1 + 1/C2 + 1/C3

The Attempt at a Solution

So on the right most of the diagram, C1 and C are in series, hence their combined capacitor is C1(C)/C1+C. And since the combined capacitor is in parallel with the other C1, C equivalent is C1(C)/C1+C + C1 = C

However, I can't seem to solve that particular equation by making C as the subject...

Please help..

The answer provided by the textbook is:
C=C1 (1+ square root of 5) / 2

Thanks...

 

[CR9]

I guess my diagram is messed up even though i tried to fixed it, but yeah,

C1 is in series with C

and those two combined are in parallel with C1...

 

[gneill]

Let's see some of the mathematical steps you've taken to try to solve for C.