How Do You Calculate the Force of Tension in a Pendulum Rope?

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SUMMARY

The discussion focuses on calculating the force of tension in a pendulum rope, specifically for a bowling ball weighing 71.2 N attached to a 3.90 m rope. At the lowest point of the swing, the ball's speed is measured at 4.30 m/s, leading to an acceleration of 4.74 m/s². To determine the tension in the rope (FT), it is essential to consider both gravitational force (mg) and centripetal force (mv²/R). The correct approach involves setting the net force equal to ma, rather than relying solely on FT = ma.

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enantiomer1
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A bowling ball weighing 71.2 N is attached to the ceiling by a 3.90 m rope. The ball is pulled to one side and released; it then swings back and forth like a pendulum. As the rope swings through its lowest point, the speed of the bowling ball is measured at 4.30 m/s

I've figured out that acceleration = 4.74 m/s2
Now all I need to know is the force of tension in the rope , I've tried FT= ma
but that isn't working so I'm stuck
anyone know what equation I'm missing?
 
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If the question is what is the tension of the rope at the lowest point, then you should be thinking in terms of both mg and mv2/R.
 
enantiomer1 said:
I've tried FT= ma
but that isn't working so I'm stuck
That would work if Ft was the only force acting on the ball, but it's not. Set the net force equal to ma.
 

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