Vectors Homework: Displacement & Direction at 80°

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Homework Help Overview

The problem involves calculating the displacement vector of a person on a Ferris wheel after it has rotated by an angle of 80 degrees. The context is centered around circular motion and vector analysis, specifically focusing on the geometry of the situation and trigonometric relationships.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss using Cartesian coordinates to find the displacement vector by comparing two points on the circle. Some suggest drawing sketches to visualize the problem, while others express confusion about their calculations and the application of trigonometry.

Discussion Status

There is ongoing exploration of different methods to approach the problem, including the use of trigonometry and vector addition. Some participants have provided hints and suggestions for checking calculations, while others express uncertainty about their results. Multiple interpretations of the problem setup are being considered.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the resources they can use. There is also a discussion about the nature of the triangle formed by the center of the wheel and the positions of the person at different angles.

Rob123456789
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Homework Statement


You go to an amusement park with your friend Betty, who wants to ride the 90-m-diameter Ferris wheel. She starts the ride at the lowest point of a wheel that, as you face it, rotates counterclockwise.

What is the magnitude of her displacement vector when the wheel has rotated by an angle of 80 ∘?
and
What is the direction of her displacement vector when the wheel has rotated by an angle of80 ∘, measured counterclockwise from the horizontal?

Homework Equations


I have no idea how to do this.

The Attempt at a Solution


I tried doing 45tan(80), but its gives me a wrong answer.
 
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You are comparing two points in a circle of radius 45 m (take the centre of the wheel to be the origin). Write their Cartesian coordinates and take the difference: that will be your displacement vector.
 
My hint would be to draw a sketch of the situation. In the sketch, show the Ferris wheel, the displacement vector, and the 80o angle.

You can use the sketch as an aid to carrying out Lucas' approach. Or, you might be able to get the magnitude of the displacement with a little trig applied to the sketch.
 
Yes, I am trying to do it with trig, but it seems to give me a wrong answer?
 
Can you guys show me how to do it with trig? I feel like I'm just stuck.
 
Consider the triangle with the following vertices: the centre of the wheel, Betty's initial point and Betty's final point. You know one of the angles and you know two of the side lengths. Note that it is not a right angle triangle.

If you make a sketch of this triangle and use some trig knowledge you should be able to find the magnitude.
 
I keep getting √(52.8)^2+(44)^2 = 69 , but it's telling me I am wrong ? I added both of the vectors's components...
 
Rob123456789 said:
I added both of the vectors's components...
which vectors?
 
The (0,45) and (7.8,44) calculated from trig
 
  • #10
Rob123456789 said:
The (0,45) and (7.8,44) calculated from trig
Can you describe what the first vector (0, 45) represents? Is it the vector drawn from the initial location of Betty to the center of the Ferris wheel?
Likewise, what does the vector (7.8,44) represent?
 
  • #11
Rob123456789 said:
The (0,45) and (7.8,44) calculated from trig
Adding these components should give the right displacement vector. I think you messed up on adding the components, so you got the wrong magnitude.
 
  • #12
Check to see if you might have the x and y components interchanged in (7.8, 44) and check the signs of the components.
 
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  • #13
Toss Cartesia.

A line joining two points on a circle is called a chord. The length of a chord can be determined by joining the two endpoints to the center of the circle - thus forming an isosceles triangle - and applying some trigonometry.
 
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  • #14
You'd get an Issoceles triangle with sides of 45 m with an angle of 80 degrees between them. Using the cosine rule, you should get an answer of 57.85 m. I hope this helps.
 
  • #15
Rob123456789 said:
Yes, I am trying to do it with trig, but it seems to give me a wrong answer?

I would suggest you avoid as much trig as you can; you will need some, of course, but do NOT make this an exercise in trigonometric manipulations and trig function properties, or a problem in Euclidean geometry. The problem is about finding a vector, and is (I bet) designed to help you think about vectors and how to use them. There are well-structured methods for doing that, and these become straightforward with a bit of practice. This exercise is about getting some of that practice.

Here you have two vectors: (i) a vector pointing vertically upward, from the ground to the center of the carousel; and (ii) a vector pointing from the center of the carousel to the position of your friend. Their vector sum gives you the vector pointing from the ground to your friend, and that is what you want to find.
 

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