How Do You Calculate the Grating Spacing in a Diffraction Problem?

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Homework Help Overview

The discussion revolves around calculating the grating spacing (d) for a diffraction grating with a specified number of lines per millimeter. The subject area is diffraction and wave optics.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the meaning of d in the context of the problem, questioning its representation and units. There are attempts to clarify the relationship between the number of lines and the gap separation, as well as discussions on unit conversions.

Discussion Status

The discussion is active, with participants providing insights into the interpretation of d and its implications for the problem. Some guidance on unit conversions and the relationship between variables has been offered, but no consensus has been reached regarding the final approach to the problem.

Contextual Notes

Participants are navigating the definitions and units involved in the problem, with specific attention to the implications of converting between millimeters and meters. There is also a mention of the limitations of the sine function in relation to the diffraction equation.

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[SOLVED] Diffraction homework help

Homework Statement



calculate d for a diffraction grating with 600 lines/mm.

Homework Equations




mwavelength / d = x/ L

The Attempt at a Solution



well i really don't know what to solve for because i thought the diffraction grating is d.
 
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how would you solve for d?
 
What is d supposed to be? (what does it represent)
 
d= gap separation
 
or maybe it means put it in terms of m/lines?
 
Gap separation would be expressed in units of length, right? So if there are 600 lines per mm, how many mm is one line?
 
1.66 * 10-3 mm/Line ? is that right and then can i change it to meters to be 1.66* 10-6 m/line
 
That's how I would do it. I don't know if you need to convert to meters but there's nothing wrong with that.
 
the portion of the equation x/L is the same as oppostie/hypotenuse so the orginal equation can be written as sin (theda) = m*wavelength / d. Since sin (theda) cannot exeed 1 what is the highest order bright line which can be formed form the 6330 Anstrom (spelling of this unit is probably wrong) laser upon the 600 lines/mm diffraction grating?

i worked the problem and for the answer i got:
the 2nd order?
 
  • #10
Looks OK to me.
 

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