How Do You Calculate the Gravitational Force in a Hydrogen Atom?

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Homework Help Overview

The discussion revolves around calculating the gravitational force between an electron and a proton in a hydrogen atom, specifically when they are 1.0 x 10^-10m apart. The participants are exploring the application of the gravitational force formula, F=G m1 m2/r^2, in this context.

Discussion Character

  • Mathematical reasoning, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply the gravitational force formula but expresses confusion about how to perform the calculations. Some participants clarify the need to include the gravitational constant and suggest steps for calculating the force.

Discussion Status

Participants are actively discussing the calculation process, with some providing guidance on using a scientific calculator. There is recognition of a mistake regarding the mass of the electron, which has led to further questioning and recalculating efforts.

Contextual Notes

There is a noted confusion regarding the correct mass of the electron, which was initially stated incorrectly. This has prompted a participant to question the validity of their calculations and seek clarification.

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Homework Statement


In a hydrogen atom a electron and a proton are 1.0 x 10^-10m apart. What is the force of attraction between the two particles?



Homework Equations


F=G m1 m2/r^2



The Attempt at a Solution


electron: 9.11 * 10^31kg
Proton: 1.67 * 10^-27kg

so, Fgrav= (9.11 * 10^31kg) * (1.67 * 10^-27kg) / (1.0* 10^-10m)^2

Is this right?? And well if it is or if it isn't...how do u solve this?? I'm looking at this big equation and i don't know where to start. How do u multiply this and divide it?? I see many example problems like these and i see them going this far but them i lose them when they get the solution...how DO you get the solution??
 
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xArashix said:
so, Fgrav= (9.11 * 10^31kg) * (1.67 * 10^-27kg) / (1.0* 10^-10m)^2

you missed out the gravitational constant G = (6.67*10^-11)

Fgrav = (G*m1*m2)/(r^2)

multiply the numerator together first and divide it by the denominator.
 
so it's... F= (6.67*10^-11)*(9.11 * 10^31kg) * (1.67 * 10^-27kg) / (1.0* 10^-10m)^2??
 
xArashix said:
oh wow, so it's... F= (G*m1*m2)/(r^2)*(9.11 * 10^31kg) * (1.67 * 10^-27kg) / (1.0* 10^-10m)^2


Nope, its..

the formula is : F= (G*m1*m2)/(r^2)

so for this particular question, you need to substitute in the respective numbers..

G=(6.67*10^-11)
m1= (9.11 * 10^31kg)
m2= (1.67 * 10^-27kg)
r= (1.0* 10^-10m)

so you will get this:

F= (6.67*10^-11)(9.11 * 10^31kg)(1.67 * 10^-27kg) / (1.0* 10^-10m)^2

solve this with a calculator=)
 
xArashix said:
so it's... F= (6.67*10^-11)*(9.11 * 10^31kg) * (1.67 * 10^-27kg) / (1.0* 10^-10m)^2??

yes that's correct
 
solving it with the calculator is the problem T-T...how in the world do i type that in? I feel really stupid lol...how do u multiply the 10^11 and the others..I'm lost. And i bet once i figure this out I am going to feel soooo dumb :( you can't type that whole equation in the calculator so..i don't know ;_;
 
u need to be using a scientific calculator or a graphic calculator in order to type "10^11" are you using a scientific calculator?

and you don't have to type in the whole string of numbers in one go.

you might like to find (6.67*10^-11)*(9.11 * 10^31kg) * (1.67 * 10^-27kg) first.. followed by (1.0* 10^-10m)^2 then divide the first answer by the second answer.
 
yes i do which is making me feel a lot dumber lol

if i type (6.67*10^-11)*(9.11 * 10^31kg) * (1.67 * 10^-27kg)...i get 1.01475379E-5 O.o...that's not right is it?
 
pardon me for not spotting this mistake earlier on, you mentioned you are using electrons, so the mass on electron is 9.11*10^-31 kg NOT 9.11*10^31, you missed out a negative sign. try recalculating =)

if an electron is 9.11*10^31kg in mass, its heavier than the sun! lol!
 
  • #10
...WOW XD I am dumb lol thanks ^^
 

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