How Do You Calculate the Launch Speed of a Ball in a Pinball Machine?

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Homework Help Overview

The problem involves calculating the launch speed of a ball in a pinball machine, utilizing the principles of conservation of mechanical energy. The setup includes a spring with a specified force constant and an inclined surface.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the application of conservation of mechanical energy, questioning the initial and final potential energy states. There is confusion regarding the treatment of potential energy due to the incline and the height associated with the spring's compression.

Discussion Status

Some participants have identified the need to consider multiple forms of potential energy in the problem. There is an ongoing exploration of how to calculate the height associated with the incline and the implications of the spring's work on the ball's kinetic energy.

Contextual Notes

Participants note that the initial potential energy is not zero and that the height change due to the incline must be calculated to fully understand the energy conversion involved in the launch process.

Touchme
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The ball launcher in a pinball machine has a spring with a force constant of 1.10 N/cm (Fig. P5.71). The surface on which the ball moves is inclined 10.0° with respect to the horizontal. If the spring is initially compressed 4.00 cm, find the launching speed of a 0.100 kg ball when the plunger is released. Friction and the mass of the plunger are negligible.

I converted all the cm to m (0.011 N/m and 0.04m). I apply the Conservation of mechanical energy. Initial KE and PE is 0. I also set final PE as 0 and solved for final velocity. So I tried (1/2)(k)(x^2) = (1/2)mv^2
however it is incorrect. I also try taking the final velocity and dividing it by cos 10. Wrong and not sure why I did that :confused: . What am I doing wrong?
 

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Touchme said:
The ball launcher in a pinball machine has a spring with a force constant of 1.10 N/cm (Fig. P5.71). The surface on which the ball moves is inclined 10.0° with respect to the horizontal. If the spring is initially compressed 4.00 cm, find the launching speed of a 0.100 kg ball when the plunger is released. Friction and the mass of the plunger are negligible.

I converted all the cm to m (0.011 N/m and 0.04m). I apply the Conservation of mechanical energy. Initial KE and PE is 0. I also set final PE as 0 and solved for final velocity. So I tried (1/2)(k)(x^2) = (1/2)mv^2
however it is incorrect. I also try taking the final velocity and dividing it by cos 10. Wrong and not sure why I did that :confused: . What am I doing wrong?
The final PE is not zero. There are two sources of PE important to this problem. Furthermore, your statement that the initial PE is zero is contradicted by your equation

(1/2)(k)(x^2) = (1/2)mv^2

What this equation implies is that the initial potential energy of the spring is converted to kinetic energy of the ball. That's good as far as it goes, but it leaves out that other potential energy consideration.
 
Last edited:
If the final PE is not zero, the problem is how to determine the PE if the only distance given is the displacement from equilibrium. Furthermore, the height is unknown.
 
Touchme said:
If the final PE is not zero, the problem is how to determine the PE if the only distance given is the displacement from equilibrium. Furthermore, the height is unknown.
The plunger is on an incline. You know how far the plunger moves. When the plunger is released the spring does work on the ball equal to its stored energy. Some of that work increases the gravitiaonal potential energy of the ball because it goes up the incline. The rest of the work is the kinetic energy of the ball
 
Hmm... I think I understand now. The plunger moves 4cm because that is the distance traveled when the plunger is launched. Also the 4cm is the distance moved up an incline, so I have to find the h value (4sin10). Am I on the right track, if so then I think I can solve this?
 
Touchme said:
Hmm... I think I understand now. The plunger moves 4cm because that is the distance traveled when the plunger is launched. Also the 4cm is the distance moved up an incline, so I have to find the h value (4sin10). Am I on the right track, if so then I think I can solve this?
Yes. That is what you need.
 

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