How Do You Calculate the Length of a Crease in a Folded Notecard?

  • Thread starter Thread starter um0123
  • Start date Start date
  • Tags Tags
    Length
Click For Summary

Homework Help Overview

The problem involves a 3" x 5" notecard that is folded such that point A is on top of point B, and the goal is to find the length of the crease algebraically. Participants are discussing the geometric relationships and algebraic expressions related to the crease formed by the fold.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between points A, B, and C, questioning how to prove their distances are equal. There are attempts to derive an equation for the crease length using geometric properties and algebraic manipulation.

Discussion Status

Some participants have provided algebraic expressions and attempted to solve for variable x, while others are questioning the order of operations in their calculations. There is ongoing exploration of the congruence of triangles formed by the fold, but no consensus has been reached on a definitive proof or method.

Contextual Notes

Participants are navigating potential confusion regarding the order of operations and the assumptions underlying the equality of distances from points A and B to point C. There is also a mention of the need for clarity on geometric principles related to congruent triangles.

um0123
Messages
151
Reaction score
0

Homework Statement



Take a 3" X 5" notecard and fold it such that point A is on top of point B. Find the length of the crease algebraically.

http://img527.imageshack.us/img527/9913/notecard.jpg

point C is a point created by me.
the dotted line is the crease.
the red line is point A to Point C.

Homework Equations



none

The Attempt at a Solution



i don't even know where to start i have realized that the distance from Point A to Point C(the red line in the diagram) is equal to Point B to Point C. But i don't know how to prove that algebraically, and i don't know how to find the length of the crease.
 
Last edited by a moderator:
Physics news on Phys.org
Here's an image of the folded card that might help you:

forumrectangle.jpg
 
so the length of h would be \sqrt{(5-2x)^2 + (3)^2}

which equals
\sqrt{4x^2-20 x+34}

i don't even know how that simplifies.
and how do i find out the correct value of x?

i feel like in not doing the correct thing.
 
Look at the left-most triangle to get an equation you can solve for x.
 
oh, i see. solving that i get x = 1.6

then if i plug it into my equation i got hot h i get \sqrt{12.24}

but i have one problem, when i plugged 1.6 into that whole equation on of the steps is \sqrt{10.24 - 32 + 34}

if you add the 32 and 34 together to get 66 before you subtract it from 10.24 you get a negative number under the sqrt, which would mean its imaginery (and we know it can't be). But if you subtract 32 from 10.24 before adding the 34 you get the answer i just posted. This would go agianst the order of operations which states addition goes first. Or is this a case where you just go left to right?

edit: also what is the rule that states that point A to point C, and point B to point C, must be equal?
 
Last edited:
for addition and subtraction, you have to do from left to right. I don't remember there is a rule that states addition goes first. Only know about do multiplication and division first, then addition and subtraction.
or if you want, you can rewrite the equation like this \sqrt{10.24-(32-34)}.
 
um0123 said:
oh, i see. solving that i get x = 1.6

then if i plug it into my equation i got hot h i get \sqrt{12.24}



edit: also what is the rule that states that point A to point C, and point B to point C, must be equal?

The square root of 12.24 , or approximately 3.498 is correct.

If you look at the picture I drew, the line on top of AC unfolds to give line CB. My picture isn't perfectly to scale.
 
LCKurtz said:
The square root of 12.24 , or approximately 3.498 is correct.

If you look at the picture I drew, the line on top of AC unfolds to give line CB. My picture isn't perfectly to scale.

i see that, but i was wondering if there is a proof rule that i can state. or is it just assumed?
 
um0123 said:
i see that, but i was wondering if there is a proof rule that i can state. or is it just assumed?

If you label the lower right corner of the original rectangle D and the lowest point on the dotted line triangle at the bottom E, triangles ACE and CBD are congruent:

AE = BD = 3, (they are the same edge of the paper)

CE = CD = x (they are also the same edge)

and the included right angle. AC and BC are the equal hypotenuses.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 11 ·
Replies
11
Views
5K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 8 ·
Replies
8
Views
4K