How Do You Calculate the Magnitude and Argument of a Complex Number?

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Homework Help Overview

The problem involves calculating the magnitude and argument of a complex number given by the expression z = i/(6i - 3). Participants are exploring methods to simplify the expression and derive the necessary components for the magnitude and argument.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss rationalizing the denominator to eliminate imaginary numbers and express z in the form a + bi. There are attempts to calculate the magnitude using the complex conjugate, but uncertainty remains about the correctness of these steps.

Discussion Status

The discussion is ongoing, with various participants suggesting methods to simplify the expression and questioning the steps taken. Some guidance has been offered regarding rationalizing the denominator, but no consensus has been reached on the correct approach or final calculations.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the information they can provide or the methods they can use. There is also a focus on ensuring the correct form of the complex number before proceeding with calculations.

Benzoate
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Homework Statement




calculate the magnitude of z= i/(6i-3) and the argument of the real and imaginary parts

Homework Equations





The Attempt at a Solution



z=i/6i-3

z*=i/-3+6i?

mag(z)=zz*

not sure if z* is correct.
 
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In that kind of problem, you want to get the imaginary numbers out of the denominator. What can you multiply both the top and bottom by, to get rid of the complex denominator?
 
berkeman said:
In that kind of problem, you want to get the imaginary numbers out of the denominator. What can you multiply both the top and bottom by, to get rid of the co8mplex denominator?

zz*=i/6i-3*(-3+6i/-3+6i)=6-3i/(45)=
sqrt((6/45)^2+(3/45)^2)=.15=mag(z)

how would I fine arg(z),Re(z),and Im(z)?
 
Benzoate said:
zz*=i/6i-3*(-3+6i/-3+6i)=6-3i/(45)=
sqrt((6/45)^2+(3/45)^2)=.15=mag(z)

how would I fine arg(z),Re(z),and Im(z)?

Don't try to do ZZ* first. Show us how you rationalize the denominator first, okay?
 
The complex conjugate of i/(6i- 3) is -i/(-6i-3)= i/(6i+3). You need the negative on both "i"s.

But as Berkman said, it is better to get z in the form a+ bi first by rationalizing the denominator.
 

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