How Do You Calculate the Mass of Silver Using Constant Pressure Calorimetry?

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SUMMARY

The mass of silver can be calculated using the principles of constant pressure calorimetry. Given the specific heat of silver as 0.235 J/g°C and water as 4.184 J/g°C, the heat lost by the silver equals the heat gained by the water. Using the equation q = m * s * ΔT, where q is heat, m is mass, s is specific heat, and ΔT is the change in temperature, the final equation simplifies to solve for the mass of silver based on the temperature changes observed.

PREREQUISITES
  • Understanding of specific heat capacity
  • Familiarity with the principles of calorimetry
  • Proficiency in algebra for solving equations
  • Knowledge of temperature conversion and measurement
NEXT STEPS
  • Review the concept of heat transfer in calorimetry
  • Study the derivation of the calorimetry equation q = m * s * ΔT
  • Practice problems involving heat exchange between different substances
  • Explore the effects of different materials on calorimetry results
USEFUL FOR

Chemistry students, educators, and anyone involved in thermal analysis or calorimetry experiments.

Bulc9408
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PRoblem statement-
The specific heat of silver is 0.235J/gC and the specific heat of water is 4.184J/gC. A piece of silver at 94.31C was dropped into a constant pressure calorimeter containing 148g of water at 24.08C. The final temperature of the water and silver was 25.39C. Assuming that the calorimeter itself absorbs a negligible amount of heat, whatw as the mass of the silver?

This is the problem at hand, and I am on the tail end of a large study period and have finished a worksheet minus this particular problem. I would appreciate the help. Thanks.
I just don't not understand what equations to use/ how to modifythem
q=m.s.(change in temp). q=C(change in temp)?
 
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heat lost by silver = heat gained by water

heat = mass x specific heat x change in temperature

It leads to one simple equation that you have to solve for silver mass.
 

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