Calorimetry Lab: Find Heat Absorbed by Water

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SUMMARY

The discussion focuses on calculating the heat absorbed by water during a calorimetry lab experiment. The key equation used is q = m * c * ΔT, where 'm' represents mass, 'c' is the specific heat, and 'ΔT' is the change in temperature. To determine the mass of water, it is established that with a density of 1.0 g/mL, the volume in milliliters directly translates to grams. This conversion simplifies the calculation of heat absorbed.

PREREQUISITES
  • Understanding of calorimetry principles
  • Familiarity with the equation q = m * c * ΔT
  • Knowledge of specific heat capacity
  • Basic skills in unit conversion (mL to grams)
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This discussion is beneficial for students conducting chemistry experiments, educators teaching calorimetry, and anyone interested in thermodynamic calculations related to heat transfer in solutions.

P-Illiterate
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I did a calorimetry lab and here's my result
[PLAIN]http://img230.imageshack.us/img230/2953/fullscreencapture111420.jpg

I'm supposed to find the heat absorbed by the water in the calorimeter, assuming the density of the solution to be 1.0 g/mL

I kniow I have to use the equation
q-rxn-mass*specific heat *change in temp.

but how do i find the mass of water.
Please help me
 
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If you have a measurement of water in milliliters, and they give you the density of 1.0 g/mL, you can assume that milliliters=grams. That should give you the mass of water.

I'm not sure what else you're asking, but we did a lab pretty similar to this not too long ago, so just let me know if you need help!
 

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