How Do You Calculate the Minimum Stopping Distance for a Car?

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Homework Help Overview

The discussion revolves around calculating the minimum stopping distance for a car traveling at a certain speed, specifically addressing the relationship between speed, friction, and stopping distance. The original poster expresses confusion about the problem and seeks guidance on how to approach it.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants suggest using energy conservation principles and discuss the roles of kinetic energy and friction in determining stopping distance. There are questions about the relevance of static versus kinetic friction and the application of energy equations.

Discussion Status

Some participants have offered guidance on using energy equations and the concept of work related to stopping forces. Multiple interpretations of the problem are being explored, particularly regarding the types of friction involved and their implications for the calculations.

Contextual Notes

The original poster notes that this is not a formal homework problem but rather a personal challenge, which may influence the nature of the discussion and the level of detail sought. There is also a mention of the potential confusion between static and kinetic friction in the context of stopping distances.

the_quack
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I that nerd that does those extra problems in the back, the really hard ones, just for the heck of it.

Well, there is one that has me really stumped.

Show that the minimum stopping distance for an auto traveling at speed 'V' is equal to '(v^2)/(2Mg)'.
(I use M for the coefficient of static friction)

Maybe I'm just dumb, but I don't know where to start.

Can someone give me a little hint? It's not actually a homework problem, but I literally go CRAZY if I can't solve a problem I try...

Does it maybe have something to do with the basicx equation of 'V^2=V.^2+2ad'?
 
Last edited:
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Well draw a block diagram first off.

There are going to be two energy equations and you need to apply the conservation of energy. One energy is going to be the kinetic energy as the car is moving. The other energy is going to be working in the opposite direction and it is due to kinetic friction (not static).
 
the_quack said:
I that nerd that does those extra problems in the back, the really hard ones, just for the heck of it.

Well, there is one that has me really stumped.

Show that the minimum stopping distance for an auto traveling at speed 'V' is equal to '(v^2)/(2Mg)'.
(I use M for the coefficient of static friction)

Maybe I'm just dumb, but I don't know where to start.

Can someone give me a little hint? It's not actually a homework problem, but I literally go CRAZY if I can't solve a problem I try...

Does it maybe have something to do with the basicx equation of 'V^2=V.^2+2ad'?
Use conservation of energy. Kinetic energy lost must be due to force of friction acting over the stopping distance. To find the minimum stopping distance use the maximum value of static friction, which is [itex]\mu_sN = \mu_smg[/itex]

The coefficient of static friction is used because the tires are not skidding. If you skid, it takes longer to stop because the coefficient of kinetic friction is smaller. The question asks for the minimum stopping distance. [The force of static friction does not actually do the work in stopping the car. Rather the forces of kinetic friction on the brakes of the car do this. But those forces are limited by the force of static friction.]

AM
 
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Man, I guess I am just dumb but I couldn't figure it out...
 
the_quack said:
Man, I guess I am just dumb but I couldn't figure it out...
If you take my suggestion and use an energy approach, you have to understand what energy is: Work = Energy = Force x distance. What is the energy that has to be expended by application of the stopping force? (what is the kinetic energy of the car?)

Just use: kinetic energy of car = stopping force x stopping distance.

AM
 

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