How Do You Calculate the Net Force on a Moving Object Using Newton's Second Law?

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To calculate the net force on a 3.00kg object moving in a plane at t=2.00s, the second derivatives of the position functions x=5(t^2)-1 and y=3(t^3)+2 are needed to find the acceleration in both x and y directions. Once the acceleration components are determined, they can be combined to find the total acceleration vector. The net force can then be calculated using Newton's second law, F=ma, by multiplying the mass by the acceleration vector. This approach effectively allows for the determination of the net force acting on the object. The discussion confirms that taking the second derivative is the correct method to find acceleration.
saber1357
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Homework Statement


A 3.00kg object is moving in a plane, with its x and y coordinates given by x=5(t^2)-1 and y = 3(t^3) + 2, where x and y are in meters and t is in seconds. Find the magnitude of the net force acting on this object at t=2.00s


Homework Equations



F = ma

The Attempt at a Solution



Can I take the second derivative of both those function to get the x and y coordinates of acceleration, plugging in t and then solving for the vector?
 
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saber1357 said:

Homework Statement


A 3.00kg object is moving in a plane, with its x and y coordinates given by x=5(t^2)-1 and y = 3(t^3) + 2, where x and y are in meters and t is in seconds. Find the magnitude of the net force acting on this object at t=2.00s


Homework Equations



F = ma

The Attempt at a Solution



Can I take the second derivative of both those function to get the x and y coordinates of acceleration, plugging in t and then solving for the vector?

yup. that gives acceleration. Then force is just m\vec{a}
 
Thank you <3
 
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