How Do You Calculate the Net Force on a Moving Object Using Newton's Second Law?

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SUMMARY

The discussion focuses on calculating the net force acting on a 3.00 kg object using Newton's Second Law, represented by the equation F = ma. The object's motion is defined by the equations x = 5(t^2) - 1 and y = 3(t^3) + 2. To find the net force at t = 2.00 seconds, participants confirm that taking the second derivative of the position functions yields the acceleration components, which can then be multiplied by the mass to determine the force vector.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Knowledge of calculus, specifically differentiation
  • Familiarity with vector components in physics
  • Basic algebra for manipulating equations
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  • Learn how to compute derivatives of parametric equations
  • Study vector representation of forces in physics
  • Explore examples of calculating net force in two-dimensional motion
  • Investigate the implications of mass on acceleration and force
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Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators looking for practical examples of applying Newton's laws in problem-solving scenarios.

saber1357
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Homework Statement


A 3.00kg object is moving in a plane, with its x and y coordinates given by x=5(t^2)-1 and y = 3(t^3) + 2, where x and y are in meters and t is in seconds. Find the magnitude of the net force acting on this object at t=2.00s


Homework Equations



F = ma

The Attempt at a Solution



Can I take the second derivative of both those function to get the x and y coordinates of acceleration, plugging in t and then solving for the vector?
 
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saber1357 said:

Homework Statement


A 3.00kg object is moving in a plane, with its x and y coordinates given by x=5(t^2)-1 and y = 3(t^3) + 2, where x and y are in meters and t is in seconds. Find the magnitude of the net force acting on this object at t=2.00s


Homework Equations



F = ma

The Attempt at a Solution



Can I take the second derivative of both those function to get the x and y coordinates of acceleration, plugging in t and then solving for the vector?

yup. that gives acceleration. Then force is just [tex]m\vec{a}[/tex]
 
Thank you <3
 

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