How Do You Calculate the Percentage Yield of Copper Carbonate?

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SUMMARY

The discussion focuses on calculating the percentage yield of copper carbonate from a reaction involving copper sulfate and sodium carbonate. The actual yield of copper carbonate is 0.15g, and the mass of sodium carbonate used is 1.460g with a volume of copper sulfate at 28.50 mL. Participants confirm the need to determine the theoretical mass of copper carbonate by calculating moles of sodium carbonate and applying the mole ratio to find the moles of copper carbonate, followed by using the percentage yield formula. It is emphasized that sodium carbonate is in excess, thus eliminating it as a limiting reagent.

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imapeiceofwod
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I'm given that

Copper sulfate + sodium carbonate --> copper carbonate + sodium sulfate.

Mass of Sodium Carbonate 1.460g
Volume of copper sulfate 28.50 mL
Actual yield of copper carbonate is 0.15g

The question is using your data and knowing that sodium carbonate was in excess calculate the percent yield reaction with respect to the copper carbonate precipitate.

From my understand i got to find the theoretical mass of copper carbonate produced correct? but how? Would i just find the number of moles of sodium carbonate use the mole ratio to find the moles of copper carbonate. then from their find its mass. then use the % yield formula
 
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You can be right, you can be also wrong. You have to check if it is not a limiting reagent problem. But in general you are on the right track.

I suppose you know concentration of copper sulfate solution?
 
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