How Do You Calculate the Potential Function for a Vector Field?

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Homework Help Overview

The discussion revolves around finding the potential function for a given vector field, specifically the vector field F = <2xy + 5, x^2 - 4z, -4y>. Participants are exploring the process of integrating components of the vector field to derive the potential function.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to find the potential function by integrating the first component of the vector field and setting up equations based on partial derivatives. Questions arise regarding the integration process and the implications of constants introduced during integration.

Discussion Status

Participants are actively discussing the integration steps and the implications of constants in the potential function. Some guidance has been offered regarding the treatment of constants during integration, but multiple interpretations of the integration process are being explored.

Contextual Notes

There are indications of confusion regarding the treatment of constants and the integration process, particularly concerning the term -4z and its implications in the context of the potential function.

Chandasouk
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Finding potential function??

F=<2xy+5, x2-4z, -4y>

How do you get the potential function of this?

I perform it in this manner

<Fx, Fy, Fz> = <2xy+5, x2-4z, -4y>

So, Fx = 2xy+5 ; Fy = x2-4z ; Fz = -4y

I take the integral of Fx to obtain x2y+ 5x + h(y,z) = f which is the variable i am using to represent potential function.

I take the partial derivative with respect to y of f and obtain

Fy = x2 + hy(y,z). The set the two different Fy equations equal to each other

x2-4z = x2 + hy(y,z)

-4z = hy(y,z)

How do I solve from here? The -4z left over throws me off.
 
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Chandasouk said:
-4z = hy(y,z)

How do I solve from here? The -4z left over throws me off.

You know the derivative of h with respect to y. It does not depend on y, -4z can be considered a constant. Integrate.

ehild
 


Integrate with respect to y? The final answer is x^2 + 5x - 4yz

If you integrate -4z = hy(y,z) with respect to y, that leaves me with -4yz + g(z) doesn't it? What happened to that g(z)?
 
Last edited:


Derive with respect to z and compare to Fz.

ehild
 

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