How Do You Calculate the Properties of a Nucleus?

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Homework Help Overview

The discussion revolves around calculating the properties of a nucleus, focusing on its mass, volume, and density in relation to the mass number A and nucleon mass m_{n}. Participants explore expressions for these properties, considering the nucleus as a spherical entity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants attempt to derive expressions for the mass of a nucleus, its volume, and density based on the mass number and nucleon mass. Questions arise regarding the role of the mass number and how to express volume and density mathematically.

Discussion Status

Several participants have provided expressions for the mass and volume of the nucleus, while others seek clarification on the definitions and implications of the mass number. There is an ongoing exploration of how to calculate density using the derived expressions, with some participants noting the need for numerical values.

Contextual Notes

Participants express confusion regarding the mass number and its units, as well as the significance of the nucleon mass in calculations. There is a recognition that the problem requires expressions rather than numerical solutions, and some participants consider leaving results in terms of constants like r_{0} rather than substituting numerical values.

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Homework Statement



1. Write down an approximate expression for the mass of a nucleus in terms of mass number A and nucleon mass m_{n}

2. Assuming that the nucleus is spherical, find an expression for the volume of this nucleus in terms of A and r_{0}

3. Find a numerical value for the density of the nucleus. Use m_{n}=1.67\times10^{-27}kg

Homework Equations



Within the problem statement and solution attempt.

The Attempt at a Solution



1. I have that nuclear mass is M=A, but I don't see where m_{n} factors in.

2. Average nuclei radius: r=r_{0}A^{1/3} where r_{0} is a defined constant.

3. Obviously density is mass over volume. Using the value in part 2 for the radius, can calculate the volume of the spherical nucleus. Using this and the value of the nucleus mass given, can calculate the volume. But I don't know what A is in order to be able to get a numerical value.
 
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Lissajoux said:

Homework Statement



1. Write down an approximate expression for the mass of a nucleus in terms of mass number A and nucleon mass m_{n}

2. Assuming that the nucleus is spherical, find an expression for the volume of this nucleus in terms of A and r_{0}

3. Find a numerical value for the density of the nucleus. Use m_{n}=1.67\times10^{-27}kg

Homework Equations



Within the problem statement and solution attempt.

The Attempt at a Solution



1. I have that nuclear mass is M=A, but I don't see where m_{n} factors in.

2. Average nuclei radius: r=r_{0}A^{1/3} where r_{0} is a defined constant.

3. Obviously density is mass over volume. Using the value in part 2 for the radius, can calculate the volume of the spherical nucleus. Using this and the value of the nucleus mass given, can calculate the volume. But I don't know what A is in order to be able to get a numerical value.

1. What is the mass number?? Hint: It does not have units of mass.

2. You didn't find the volume.

3. Just divide answer from 1 with 2 to get the density.
 
1. A = Mass Number = Number of Nucleons = Number of Protons + Number of Neutrons

I don't see what's going on here, how I can get the expression or any values to get an actual numerical answer.

2. So I have the radius, and can work out the volume as:

V=\frac{4}{3}\pi\left({r_{0}A^{1/3}}\right)^{2}

3. OK so this is pretty obvious to do then once parts 1. and 2. are sorted out.
 
Lissajoux said:
1. A = Mass Number = Number of Nucleons = Number of Protons + Number of Neutrons

I don't see what's going on here, how I can get the expression or any values to get an actual numerical answer.

2. So I have the radius, and can work out the volume as:

V=\frac{4}{3}\pi\left({r_{0}A^{1/3}}\right)^{2}

3. OK so this is pretty obvious to do then once parts 1. and 2. are sorted out.

1. If I have 5 bowling bowls and each bowling ball weighs 10 pounds and i put them all in one box. How much would the box weigh? You know how much each nucleon weighs.

2. I think you meant:
V=\frac{4}{3}\pi\left({r_{0}A^{1/3}}\right)^{3}
 
Is this: m_{n}=1.67\times10^{-27}kg the mass of the nucleus or the mass of an individual nucleon? I think it's the latter, but I've got a bit confused now.

1. So using m_{n}=1.67\times10^{-27}kg, multiply this by A to get the mass of the nucleus? I don't know the value of A though.

2. Yes that is what I meant, it was a typo in the formula. So I can use the mass that I've just calculated in part 1, and the radius from initial question part 2, yep?
 
Lissajoux said:
Is this: m_{n}=1.67\times10^{-27}kg the mass of the nucleus or the mass of an individual nucleon? I think it's the latter, but I've got a bit confused now.

1. So using m_{n}=1.67\times10^{-27}kg, multiply this by A to get the mass of the nucleus? I don't know the value of A though.

2. Yes that is what I meant, it was a typo in the formula. So I can use the mass that I've just calculated in part 1, and the radius from initial question part 2, yep?

1.Write down an approximate expression for the mass of a nucleus in terms of mass number A and nucleon mass m_{n}. It is not asking for a value in this question just an expression. You have A nucleons and you know the mass of each.

3. Yep and it looks like the A's will cancel.
 
So then:

1. Mass of nucleus expressed by: M = A \times M_{n}

2. Volume of nucleus expressed by: V = \frac{4}{3}\pi\left({r_{0}A^{1/3}}\right)^{3} = \frac{4}{3}\pi r_{0}^{3}A

3. Density of nucleus expressed by: \rho = \frac{1.67\times10^{-27}}{\frac{4}{3}\pi r_{0}^{3}}\impies simplifies further?!
 
Lissajoux said:
So then:

1. Mass of nucleus expressed by: M = A \times M_{n}

2. Volume of nucleus expressed by: V = \frac{4}{3}\pi\left({r_{0}A^{1/3}}\right)^{3} = \frac{4}{3}\pi r_{0}^{3}A

3. Density of nucleus expressed by: \rho = \frac{1.67\times10^{-27}}{\frac{4}{3}\pi r_{0}^{3}}\impies simplifies further?!

Yes because you know the value of r_{0} right? It is asking for a numerical answer.
 
3. Yes I know the value of r_{0}. So can put this into give me a numerical result for the value of the nucleus density.

2. Can also put value of r_{0} into the equation for the nucleus volume, I think that will just make things look worse though than the nice expression there in terms of it.
 
  • #10
Lissajoux said:
3. Yes I know the value of r_{0}. So can put this into give me a numerical result for the value of the nucleus density.

2. Can also put value of r_{0} into the equation for the nucleus volume, I think that will just make things look worse though than the nice expression there in terms of it.

1. Yep, looks good!

2. Of course, you can put the numerical value of r_{0} into any equation that contains r_{0}. Your problem (#2) asks for an expression involving r_{0} and A though.
 
  • #11
Great! =D

In regards to 2. I think will leave it in terms of r_{0} and maybe just state the value of it separately below.
 

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