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bagwellaj
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Electricity/Potential Difference
A cylindrical copper cable carries a current of 1060 A. There is a potential difference of 1.6 x 10^-2 V between two points on the cable that are .26 m apart. What is the radius of the cable?
R= V/I R= p(L/A) There may be more formulas needed.
p of Copper is 1.72 x 10^-8
I divided the given V by the given current to get the resistance, which came out to be 1.509 x 10^-5. I plugged that into R= p(L/A) using 1.72 x 10^-8 for p, .26 for L, and (pi)(r^2) for A. I solved for r this way and got 9.712 x 10^-3 m. Is this right?
Homework Statement
A cylindrical copper cable carries a current of 1060 A. There is a potential difference of 1.6 x 10^-2 V between two points on the cable that are .26 m apart. What is the radius of the cable?
Homework Equations
R= V/I R= p(L/A) There may be more formulas needed.
p of Copper is 1.72 x 10^-8
The Attempt at a Solution
I divided the given V by the given current to get the resistance, which came out to be 1.509 x 10^-5. I plugged that into R= p(L/A) using 1.72 x 10^-8 for p, .26 for L, and (pi)(r^2) for A. I solved for r this way and got 9.712 x 10^-3 m. Is this right?
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