How Do You Calculate the Sedimentation Coefficient of Escherichia coli?

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SUMMARY

The discussion focuses on calculating the sedimentation coefficient of Escherichia coli using the provided molecular weight, specific volume, and experimental data. The equation M=(RTs)/(D(1-(ρf * Vo)) is central to the calculation, where R is the gas constant (8.31 m²kgmol⁻¹s⁻²K⁻¹). The user encountered difficulties in determining the values for ρf and Vo, leading to a division by zero error. Clarification on these parameters is essential for completing the sedimentation coefficient calculation.

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Homework Statement


Escherichia coli data:
molecular weight = 74000g/mol
specific volume = 0.737cm3/g
temperature = 293 K

In a dilute aqueous buffer (0.02M potassium phosphate) at 293.75 K
speed of rotation = 56050 rpm

gave the following results:

Time (min)...x1/2
0.....5.9
20...6
40...6.1
60...6.2
80...6.3
100.....6.4
120.... 6.5
140.....6.6


Homework Equations


This is the equation given to us:

M=(RTs)/(D(1-([tex]\rho[/tex] f *V o))


The Attempt at a Solution


I used an R value of 8.31m2kgmol-1s-2K-1

I rearranged the equation to equal s

However, I got stuck at [tex]\rho[/tex]f*Vo. Using the [tex]\rho[/tex] and V given in the question results in a division by 0.

Could someone explain to me how I find [tex]\rho[/tex] f and V o? I don't need anyone to solve the question, I would like to do that on my own.
 
Last edited:
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I'm sorry for the terrible equations.
The rho is supposed to be rho with a subscript f, and V is V subscript o
 

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