How Do You Calculate the Slit Spacing in a Double-Slit Experiment?

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SUMMARY

The discussion focuses on calculating the slit spacing in a double-slit experiment using a helium-neon laser with a wavelength of 590 nm. The setup involves a screen positioned 3.42 m from the slits, where twelve bright fringes are observed over a distance of 47 mm. The calculated spacing between the slits is determined to be approximately 4.73 x 10^-4 m, or 0.473 mm. Participants emphasize the importance of clearly labeling variables and understanding the behavior of light in this context.

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Homework Statement


Light from a helium-neon laser (λ=590 nm) is used to illuminate two narrow slits. The interference pattern is observed on a screen 3.42 m behind the slits. Twelve bright fringes are seen, spanning a distance of 47 mm. What is the spacing (in mm) between the slits?


Homework Equations





The Attempt at a Solution


t = wavelength

t= 590 nm
L = 3.42 m
y = 47 mm
12 fringes
so the space between 2 fringes would be 47mm/11 = 4.27 mm

d = tL/y = 4.73 x 10^-4 m

I don't have the answer to this problem so is this the right way to do this?
 
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Does anyone know if this is right?
 
BuBbLeS01 said:
Does anyone know if this is right?

your variables are a bit confusin. try labeling them. also, are you saying that the light is coming straight out? (because light doesn't usually stay in a straight beam, does it)
 

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