MHB How Do You Calculate the Slope to Intercept a Moving Point?

  • Thread starter Thread starter AlienNova
  • Start date Start date
  • Tags Tags
    Slope Speed
AI Thread Summary
To calculate the slope for a moving point, the standard slope formula (y2 - y1)/(x2 - x1) needs to be adapted for the moving point, referred to as point A. When point A is in motion, its position can be described using parametric equations based on its speed and direction, such as x(t) = t + c and y(t) = t + d, where c and d are the starting coordinates. The slope of the path can be determined by knowing the trajectory's slope and the initial coordinates. An example demonstrates this with a slope of 3/2 and a starting position of (3, 2), leading to specific equations for x(t) and y(t). Understanding these concepts allows for the calculation of the slope as the moving point approaches another point.
AlienNova
Messages
2
Reaction score
0
Sorry for the very confusing title, I couldn't think of a different way to better explain my question shortly. Also please bare with me, I find this very hard to explain.

So I'm trying to find the slope between two points when one point is moving in a set direction with a set speed. Confused? I'm not the best with words.

Okay, so normally to find the slope of two points you use the simple formula (y2 - y1)/(x2 - x1). That's the quickest way to intersect a point (Now on going to be called point A) if point A is stationary. But what if point A is moving (In a set direction, not turning)?

Say point A is a someone you want to talk to, and they're walking. When walking to them you don't walk straight at them, you walk to a point where your two paths will cross at the same time. My question is how do you find the slope you decided to walk?

Hopefully that didn't just make things more complicated to understand. Any help will be appreciated!
 
Mathematics news on Phys.org
You could use parametric equations, if you have enough data.
Say the slope of the path of the moving object is 1. Then
x(t) = t + c and y(t) = t + d, where c and d are the starting
x and y coordinates, respectively. So you'd need to know
the slope of the trajectory of the moving object and the x and y
coordinates of its starting position.

Another example: Slope 3/2, (time, t, in seconds) and a starting position of (3, 2):

x(t) = 2t + 3, y(t) = 3t + 2.

For your problem you may then compute (y2 - y(t))/(x2 - x(t)).
 
Last edited:
Thank you so much, it took me a couple read throughs but I understand it now!
 
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Back
Top