How do you calculate the specific heat capacity of nickel?

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Discussion Overview

The discussion revolves around calculating the specific heat capacity of nickel using a calorimetry experiment involving a nickel sample and water. Participants explore the necessary equations and considerations for determining the specific heat capacity in the context of a homework problem.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant presents a calorimetry problem involving a nickel sample and water, seeking to calculate the specific heat capacity of nickel.
  • Another participant identifies the specific heat capacity of water as a constant value, specifically 4.18 J/Kg.
  • Some participants note that the specific heat capacity of water varies with temperature, referencing a source that lists different values for water at various temperatures.
  • One participant expresses uncertainty about the specific heat capacity of water at 13.5 degrees Celsius, suggesting that it should still be approximately 4.1813 J/Kg.
  • A later reply mentions that while specific heat can vary with temperature, it is often assumed to be constant for practical calculations within certain temperature ranges, particularly for water and metals.

Areas of Agreement / Disagreement

Participants express differing views on whether the specific heat capacity of water can be treated as constant in this scenario. Some agree that it is reasonable to use a constant value, while others emphasize the importance of temperature dependence.

Contextual Notes

There is a lack of consensus on the specific heat capacity of water at 13.5 degrees Celsius and whether it should be treated as constant for the purposes of this calculation. The discussion also highlights potential variations in specific heat capacities with temperature.

dav1d
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Homework Statement



A 28.2 g sample of nickel is heated to 100 degrees C and placed in a coffee cup calorimeter containing 150g of water at a temperature of 13.5 degrees C. After the metal cools, the final temperature of the metal and water is 25 degrees C. Calculate the specific heat capacity of nickel.


Homework Equations



Q=mcdeltaT

The Attempt at a Solution



first calculate Q for water.
Q=mcT
=(150g)

But what is c for water at 13.5degrees? Problem, now I don't know what to do from here.
 
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c = the specific heat capacity which is a constant or a material ie. the specific heat capacity for water is 4.18 JK^-1g^-1 ;)
 
dav1d said:
Um, water has different c values at different temperatures.

http://en.wikipedia.org/wiki/Heat_capacity#Table_of_specific_heat_capacities

Water at 100 °C (steam) gas 2.080 37.47 28.03
Water at 25 °C liquid 4.1813 75.327 74.53 4.1796
Water at 100 °C liquid 4.1813 75.327 74.53 4.2160
Water at −10 °C (ice)[20] solid 2.11 38.09 1.938
not according to my textbook. I think that specific heat capacitys must change when they states are change. If that is that case, at 13 degrees, water should still be 4.1813. (I'm only making assumptions here)
 
As explained in other thread - specific heat is a function of temperature, but differences are usually small enough that we can assume it is constant - as long as the substance doesn't change its state. This is especially true for water and most metals between 0-100°C. Use 4.18 J/Kg and don't worry.
 
Sorry. Will fix later.
 

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