(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Finding the specific heat capacity of an unknown metal.

A cylinder was placed into boiling water, originally at 24.2 C. The heat transfered from the metal, and the water then was 29.5 C.

Original Temperature-24.2 C

Temperature after the metal has been placed into the water.-29.5 C

m=mass of water (100 g)

C=Specific Heat of Water (1 C)

deltaT=Change of Temperature in water=5.3 (29.5-24.2)

Metal

M=Mass of metal (86.79 g)

deltaT=? (I think it is 5.3, equivalent to the change of temperature in the water)

C=?

I am not entirely sure what I am doing wrong. I thought that the heat gained by the water is equivalent to the heat lost by the metal, therefore the change

2. Relevant equations

Q=mCdeltaT

Q/m*deltaT=c

3. The attempt at a solution

First I found the heat gained by the water by using the formula Q=mCdeltaT.

Where

m=mass of water (100 g)

C=Specific Heat of Water (1 C)

deltaT=Change of Temperature in water=5.3 (29.5-24.2)

Q=100x1x5.3

Therefore Q=530

Next, I used the Q to calculate the specific heat capacity of the unknown metal.

Q=mCdeltaT, with the variables changed to Q/m*deltaT=c

Where

Q=Heat Gained by Water/Lost by metal (530)

m=Mass of metal (86.79 g)

deltaT=This is what I am unsure about. Would the heat lost by the metal be equivalent to the heat gained by the water? Which would equal to 5.3 C.

If I calculate using that assumption for Delta T the answer equals 1.15 c/ g cal which is quite high for the specific heat capacity of a metal.

Was my process correct?

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Specific Heat Capacity of a cylinder in boiling water

**Physics Forums | Science Articles, Homework Help, Discussion**