How Do You Calculate the Speed of a Boat Relative to Water?

Click For Summary
SUMMARY

The discussion focuses on calculating the speed of a motorboat relative to the water while accounting for the current of a stream flowing at 3.4 km/hr. The motorboat travels a total distance of 10.2 km (5.1 km each way) in 1.5 hours. The correct approach involves using the distance-speed-time relationship rather than vector components, leading to the equation: distance = speed × time for both upstream and downstream travel. The solution reveals that the speed of the boat relative to the water is 8.0 km/hr.

PREREQUISITES
  • Understanding of basic physics concepts such as velocity and relative motion.
  • Familiarity with the distance-speed-time relationship.
  • Ability to set up and solve algebraic equations.
  • Knowledge of how to analyze motion in different directions (upstream and downstream).
NEXT STEPS
  • Study the principles of relative velocity in fluid dynamics.
  • Learn how to apply the distance-speed-time formula in various scenarios.
  • Explore problems involving motion in currents and streams.
  • Practice setting up equations for motion in opposite directions.
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and motion, as well as educators looking for examples of relative velocity problems.

Elbobo
Messages
145
Reaction score
0

Homework Statement


Two boat landings are 5.1 km apart on the
same bank of a streamthat flows at 3.4 km/hr.
A motorboat makes the round trip between
the two landings in 1.5 hr.
What is the speed of the boat relative to
the water? Answer in units of km/hr.


Homework Equations





The Attempt at a Solution


I tried to get the velocity of the water relative to the shore plus the velocity of the boat relative to shore to equal the velocity of the boat relative to the water.

That would give a right triangle with Vws and Vbs as the legs, and Vbw (what I'm trying to find) as the hypotenuse.

So I get sqrt ( (5.1 / 0.75)^2 + 3.4^2), which is 7.60 and wrong.

Please help me, I don't understand what I am doing wrong...
 
Physics news on Phys.org
Elbobo said:
I tried to get the velocity of the water relative to the shore plus the velocity of the boat relative to shore to equal the velocity of the boat relative to the water.
velocity(boat/shore) = velocity(boat/water) + velocity(water/shore)

There's no need for any right triangles, since all velocities are in the same (or opposite) direction.

Hint: Use distance = speed*time
Set up that equation for when the boat's going upstream and for when its going downstream.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
4
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
7K
  • · Replies 8 ·
Replies
8
Views
7K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K