How Do You Calculate the Tension in a Rope Holding a Suspended Box at an Angle?

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SUMMARY

The discussion focuses on calculating the tension in a rope holding a 2kg box suspended at a 37-degree angle from the vertical. The user initially calculated the tension as 32.5 N using the equation Tsin(37) - 2*9.8 = 0 but later found the correct tension to be 14.7 N. The discrepancy arises from misunderstanding the angle's orientation, which is crucial for applying the correct trigonometric functions. Accurate application of the weight equation (w = mg) and force equations (F = ma) is essential for solving such problems.

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Homework Statement


A 2kg box is suspended to the ceiling using only one rope. A horizontal force keeps the rope at 37 degrees from the vertical. Find the tension of the rope


Homework Equations


w = mg
F = ma


The Attempt at a Solution


my understanding:
http://img507.imageshack.us/img507/8840/diagdd2.jpg
sum of y = Tsin37 - 2*9.8 = 0
T = 32.5 N
the correct answer is 14.7
please help:confused:
 
Last edited by a moderator:
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37 degrees from the vertical...you show horizontal...
 

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